Question

Graph the line that contains the point (-5,-3) and had a slope of -2

Answer 1

For this case we have that by definition, the equation of a line in the slope-intersection form is given by:

$y = mx + b$

Where:

m: Is the slope

b: Is the cut-off point with the y axis

According to the data of the statement we have to:

$m = -2$

Then, the equation is of the form:

$y = -2x + b$

We substitute the point$(x, y): (- 5, -3)$and find "b":

$-3 = -2 (-5) + b\\-3 = 10 + b\\-3-10 = b\\b = -13$

Finally, the equation is:

$y = -2x-13$

To graph we place the points $(-5, -3)$and$(0, -13)$ on the coordinate axis and join the points by a line.

ANswer:

$y = -2x-13$

The graphic is attached.