Answer: (a) P(no A) = 0.935
(b) P(A and B and C) = 0.0005
(c) P(D or F) = 0.379
(d) P(A or B) = 0.31
Step-by-step explanation: <u>Pareto</u> <u>Chart</u> demonstrates a relationship between two quantities, in a way that a relative change in one results in a change in the other.
The Pareto chart below shows the number of people and which category they qualified each public school.
(a) The probability of a person not giving an A is the difference between total probability (1) and probability of giving an A:
P(no A) = 
P(no A) = 1 - 0.065
P(no A) = 0.935
b) Probability of a grade better than D, is the product of the probabilities of an A, an B and an C:
P(A and B and C) = 
P(A and B and C) = 
P(A and B and C) = 0.0005
c) Probability of an D or an F is the sum of probabilities of an D and of an F:
P(D or F) = 
P(D or F) = 
P(D or F) = 0.379
d) Probability of an A or B is also the sum of probabilities of an A and of an B:
P(A or B) = 
P(A or B) = 
P(A or B) = 0.31
7.20+24.75=31.95
so 31.95 per student
31.95*350=11,182.50
This will cost the student body $11,182.50
5(3)-3(-2)
15-(-6)=
15+6=21
a negative plus a negative is a positive so its 21
4(3)-3(-2)
12-(-6)
12+6=18
21+18=39
Answer:
V=144
Step-by-step explanation:
To find the volume of a pyramid, use the formula V=B•h, B being the base and h the height. So 12•12=144.
Answer:
Probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.
Step-by-step explanation:
We are given that a veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses with colic is 12 years. The average age of all horses seen at the veterinary clinic was determined to be 10 years. The researcher also determined that the standard deviation of all horses coming to the veterinary clinic is 8 years.
So, firstly according to Central limit theorem the z score probability distribution for sample means is given by;
Z =
~ N(0,1)
where,
= average age of the random sample of horses with colic = 12 yrs
= average age of all horses seen at the veterinary clinic = 10 yrs
= standard deviation of all horses coming to the veterinary clinic = 8 yrs
n = sample of horses = 60
So, probability that a sample mean is 12 or larger for a sample from the horse population is given by = P(
12)
P(
12) = P(
) = P(Z
1.94) = 1 - P(Z < 1.94)
= 1 - 0.97381 = 0.0262
Therefore, probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.