An example of dependent events is drawing a green marble out of one jar and then drawing a....?

1 answer:

4 0

Dependent events involve a first event that affects the outcome of a second event. This means that the probability for the second event has changed because of the occurrence of the first event. This is usually present in probabilities without replacement because each event has a different condition. The answer is C)red marble out of the same jar,without replacing the first marble.

You might be interested in

PLS HELP ME ASAP!!!!

elena55 [62]

Answer:

2Pi/8

Step-by-step explanation:

6 0

3 years ago

Which graph represents the function f (x) = StartFraction 2 Over x minus 1 EndFraction + 4?

Pepsi [2]

Answer:

On a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 1, and the horizontal asymptote is at y = 4

Step-by-step explanation:

The given function is presented as follows;

$f(x) = \dfrac{2}{x - 1} + 4$

From the given function, we have;

When x = 1, the denominator of the fraction, $\dfrac{2}{x - 1}$ , which is (x - 1) = 0, and the function becomes, $\dfrac{2}{1 - 1} + 4 = \dfrac{2}{0} + 4 = \infty + 4 = \infty$ therefore, the function in undefined at x = 1, and the line x = 1 is a vertical asymptote

Also we have that in the given function, as x increases, the fraction $\dfrac{2}{x - 1}$ tends to 0, therefore as x increases, we have;

$\lim_ {x \to \infty} \dfrac{2}{(x - 1)} \to 0, and \ \dfrac{2}{(x - 1)} + 4 \to 4$

Therefore, as x increases, f(x) → 4, and 4 is a horizontal asymptote of the function, forming a curve that opens up and to the right in quadrant 1

When -∞ < x < 1, we also have that as x becomes more negative, f(x) → 4. When x = 0, $\dfrac{2}{0 - 1} + 4 = 2$ . When x approaches 1 from the left, f(x) tends to -∞, forming a curve that opens down and to the left

Therefore, the correct option is on a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 1, and the horizontal asymptote is at y = 4.

5 0

3 years ago

Graph the six terms of a finite sequence where a_1 = -3 and r = 1.5

marysya [2.9K]

Here's a graph of those terms.