Question

The length of Hillcrest Garden is 6 feet more than its width. A 3-foot wide walkway surrounds the outside of the garden. The total area of the walkway is 288 square feet. Find the dimensions of the garden.

Answer 1

Answer: The dimensions of the garden would be 18 feet and 24 feet.

Step-by-step explanation:

Let the width of garden be 'x'.

Let the length of garden be $'x+6'$

Since there is 3 foot wide walkway surrounds the outside the garden.

Area of walkway = 288 square feet

So, According to question, it becomes,

$2z(x+y+2z)\\\\288=2\times 3(x+x+6+2\times 3)\\\\288=6(2x+6+6)\\\\288=6(2x+12)\\\\\dfrac{288}{6}=2x+12\\\\48=2x+12\\\\48-12=2x\\\\36=2x\\\\x=\dfrac{36}{2}\\\\x=18$

Width = 18+6 =24 feet

Hence, the dimensions of the garden would be 18 feet and 24 feet.