Answer:
Step-by-step explanation:
Before adding we require the fractions to have a common denominator
The lowest common denominator of 2, 5 and 3 is 30, thus
+
+
= +
+
Add the numerators leaving the denominator
= =
b> Find the equation to the straight lines passing through (1,1) and parallel to the lines represented by x²-5xy+4y²+x+2y-2=0
1 answer:
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Given:
A line contains the points R(-1, 8), S(1, 4) and T(6, y).
To find:
The value of y.
Solution:
Three points are collinear if:
A line contains the points R(-1, 8), S(1, 4) and T(6, y). It means, these points are collinear.
Subtract 12 from both sides.
Divide both sides by 2.
Therefore, the value of y is -6.