1. What is an equation of a line, in point-slope form, that passes through (1,-7) and has a slope of -2/3?
Point Slope form y − y1 = m(x − x1)
Y1: -7 x1:1 slope :-2/3
Y-(-7)=-2/3(x-1)
Y+7=-2/3(x-1)
2. What is the equation of a line, in point-slope form, that passes through (-2,-6) and had a slope of 1/3?
Y-(-6)=1/3(x-(-2))
Y+6=1/3(x+2)
3.What is an equation in point-slope form of the line that passes through the points (4,5) and (-3,-1)
SlopeM: =change in y/change in x
M= -1-5/-3-4
M= -6/-7
M=6/7
So now slope:6/7, point (4,5)
Y-y1=m(x-x1)
Equation in point slope
Y-5=6/7(x-4)
The <em><u>correct answer</u></em> is:
D) Closed circle on 8, shading to the right.
Explanation:
First we must solve the inequality:
x - 3 ≥ 5
Add 3 to each side:
x - 3 + 3 ≥ 5 + 3
x ≥ 8
To graph this, we want a circle on 8 Since it is "greater than or equal to," 8 is included in the solution set. This means the circle will be closed.
Since it is "greater than," we want the numbers to the right of 8 on the number line.
This means the inequality will be a closed circle and shaded to the right.
Answer:
AD = 23
Step-by-step explanation:
no solutions → C
The 2 given lines are parallel and never intersect thus no solution
