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katen-ka-za [31]
2 years ago
6

A concrete slab of mass 400 kg accelerates down a concrete slope inclined at 35°. The kinetic between the slab and slope is 0.60

. Determine the acceleration of the block. ​
Physics
1 answer:
belka [17]2 years ago
8 0

I got you

Explanation:

normal force = 400 g cos 35

friction force up slope = .6 (400 g) cos 35

weight component down slope = 400 g sin 35

400 a = 400 g sin 35 - .6 (400 g cos 35)

a = g (sin 35 - .6 cos 35) = .082 g

I hope this helps you

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As the ball rolls up the inclined plane, the velocity decreases and eventually becomes zero when the ball reaches the highest point of the plane.

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The acceleration of the ball is calculate as;

a = \frac{v_f -v_0}{t} \\\\

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Learn more here:brainly.com/question/23860763

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