Answer:
The box is moved at constant speed, then the change in kinetic energy is zero.
Explanation:
Let suppose that box moves at constant speed, meaning that its kinetic energy (
), measured in joules, is expressed by the following equation:
(1)
Where:
- Mass, measured in kilograms.
- Speed, measured in meters per second.
If the box moves at constant speed, then we notice that 
, therefore, 
. In a nutshell, if the box is moved at constant speed, then the change in kinetic energy is zero.
Force = mass * acceleration
Here is an equation for force, used to calculate force.
Look at it this way:-
Joules is used to measure force, while mass is measured by kg. Acceleration is measured by m/s/s (meters per second per second, or meters per second squared.)
joules = m/s/s * kg
Which makes everything fit in just right! :D
To Predict the motion of each of the markers relative to the edges of the valley, Scientists use the Glen-Nye Flow Law.
The Glen-Nye Flow Law is then used to forecast the movement of the markers. Markers are moved and measured in relation to the valley's rim where the glacier moves.
Glaciers are a valuable resource in several places of the world. This is true because glaciers' characteristics and behaviour have an effect on the hydrologic, geologic, and biological processes in their immediate surroundings.
Because of the aforementioned, glaciologists keep an eye on glaciers and attempt to predict how they will move and look.
The usage of markers is one method employed by glaciologists in the observation and forecasting of glaciers.
Mathematical relation is:
∑= krⁿ
Where,
∑= shear strain (flow) rate
r = stress
n = a constant
k = a temperature dependent constant
Learn more about Glacier here, brainly.com/question/14309099
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Answer:
Ecu/Eag = 0.46
Explanation:
E = PI/A
Ecu = Pcu × I/A
Pcu = 1.72×10^-8 ohm-meter
r = 0.8 mm = 0.8/1000 = 8×10^-4 m
A = πr^2 = π×(8×10^-4)^2 = 6.4×10^-7π
Ecu = 1.72×10^-8I/6.4×10^-7π = 0.026875I/1
Eag = Pag × I/A
Pag = 1.47×10^-8 ohm-meter
r = 0.5 mm = 0.5/1000 = 5×10^-4 m
A = πr^2 = π × (5×10^-4)^2 = 2.5×10^-7π
Eag = 1.47×10^-8I/2.5×10^-7π = 0.0588I/π
Ecu/Eag = 0.026875I/π × π/0.0588I = 0.46
