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babymother [125]
3 years ago
7

Please Help:) How to draw two vectors being added:

Physics
1 answer:
scoray [572]3 years ago
4 0

Explanation:

you add the from head to tail. Head is the triangle and tail is the final point of the vector

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Analyze the image below and answer the question that follows.
goldenfox [79]
There are many principles that are classified under the Gestalt Principles. The Gestalt principles believe that any stimulus can be viewed in a very simple form. According to the given image, I can say that the square represents the Gestalt principle of PROXIMITY. Hope this helps.
7 0
3 years ago
Please help!!!! I will give brainliest if correct!!!
scZoUnD [109]

Answer:

The density ρ of metal block is 8.92g/cm³

So from the given density table this corresponds to copper which has density of 8.92(g/mL)

Explanation:

Oh yeah, I got the correct unit update,

Now this problem bothers on the density of substances

We know that the density of a substance is expressed as

Density ρ= mass/ volume

Given data

Mass of metal block m= 62.44g

Volume of metal block v= 7 cm³

Hence we can find the density of the metal block by plugging in our data into the expression for density

ρ of metal block = 62.44/7

ρ of metal block = 8.92g/cm³

The block is a copper block

4 0
3 years ago
Are there conditions under which the incident light ray undergoes reflection but not transmission at the boundary? if so, then w
Luden [163]

Total internal reflection causes light to be completely reflected across the  boundary between the two media but not transmitted.

<h3>What is total internal reflection?</h3>

The term total internal reflection occurs when light is moving from a denser to a less dense medium such as from glass to air. This phenomenon occurs at the interface between the two media.

There are two conditions necessary for total internal reflection and they are;

1) Light must travel from a denser to a less dense medium

2) The angle of incidence in the denser medium must be greater than the critical angle.

Total internal reflection causes light to be completely reflected across the  boundary between the two media but not transmitted.

Learn more about total internal reflection:brainly.com/question/13088998

#SPJ1

6 0
2 years ago
xConsider the following reduction potentials: Cu2+ + 2e– Cu E° = 0.339 V Pb2+ + 2e– Pb E° = –0.130 V For a galvanic cell employi
slega [8]

Answer:

Approximately \rm 90\; kJ.

Explanation:

Cathode is where reduction takes place and anode is where oxidation takes place. The potential of a electrochemical reaction (E^{\circ}(\text{cell})) is equal to

E^{\circ}(\text{cell}) = E^{\circ}(\text{cathode}) - E^{\circ}(\text{anode}).

There are two half-reactions in this question. \rm Cu^{2+} + 2\,e^{-} \rightleftharpoons Cu and \rm Pb^{2+} + 2\,e^{-} \rightleftharpoons Pb. Either could be the cathode (while the other acts as the anode.) However, for the reaction to be spontaneous, the value of E^{\circ}(\text{cell}) should be positive.

In this case, E^{\circ}(\text{cell}) is positive only if \rm Cu^{2+} + 2\,e^{-} \rightleftharpoons Cu is the reaction takes place at the cathode. The net reaction would be

\rm Cu^{2+} + Pb \to Cu + Pb^{2+}.

Its cell potential would be equal to 0.339 - (-0.130) = \rm 0.469\; V.

The maximum amount of electrical energy possible (under standard conditions) is equal to the free energy of this reaction:

\Delta G^{\circ} = n \cdot F \cdot E^{\circ} (\text{cell}),

where

  • n is the number moles of electrons transferred for each mole of the reaction. In this case the value of n is 2 as in the half-reactions.
  • F is Faraday's Constant (approximately 96485.33212\; \rm C \cdot mol^{-1}.)

\begin{aligned}\Delta G^{\circ} &= n \cdot F \cdot E^{\circ} (\text{cell})\cr &= 2\times 96485.33212 \times (0.339 - (-0.130)) \cr &\approx 9.0 \times 10^{4} \; \rm J \cr &= 90\; \rm kJ\end{aligned}.

5 0
3 years ago
A steel ball bearing is released from a height H and
ArbitrLikvidat [17]

Answer:

ELASTIC collision

kinetic energy is conservate

Explanation:

As the ball bounces to the same height, it can be stated that the impact with the floor is ELASTIC.

As the floor does not move the conservation of the moment

            po = pf

            -mv1 = m v2

- v1 = v2

So the speed with which it descends is equal to the speed with which it rises

Therefore the kinetic energy of the ball before and after the collision is the same

4 0
3 years ago
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