Answer:
The first car has the most kinetic energy.
Explanation:
Given that,
For first car
Mass of car = 1500 kg
Speed of car = 5 m/s
For second car
Mass of car = 1300 kg
Speed of car = 3 m/s
For third car
Mass of car = 1200 kg
Speed of car = 2 m/s
For fourth car
Mass of car = 1400 kg
Speed of car = 4 m/s
The kinetic energy is defined as,
![K.E=\dfrac{1}{2}mv^2](https://tex.z-dn.net/?f=K.E%3D%5Cdfrac%7B1%7D%7B2%7Dmv%5E2)
Where, m = mass
v = velocity
The kinetic energy of first car,
![K.E =\dfrac{1}{2}\times1500\times(5)^2](https://tex.z-dn.net/?f=K.E%20%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes1500%5Ctimes%285%29%5E2)
![K.E=18750\ J](https://tex.z-dn.net/?f=K.E%3D18750%5C%20J)
The kinetic energy of second car,
![K.E =\dfrac{1}{2}\times1300\times(3)^2](https://tex.z-dn.net/?f=K.E%20%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes1300%5Ctimes%283%29%5E2)
![K.E=5850\ J](https://tex.z-dn.net/?f=K.E%3D5850%5C%20J)
The kinetic energy of third car,
![K.E =\dfrac{1}{2}\times1200\times(2)^2](https://tex.z-dn.net/?f=K.E%20%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes1200%5Ctimes%282%29%5E2)
![K.E=2400\ J](https://tex.z-dn.net/?f=K.E%3D2400%5C%20J)
The kinetic energy of fourth car,
![K.E =\dfrac{1}{2}\times1400\times(4)^2](https://tex.z-dn.net/?f=K.E%20%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes1400%5Ctimes%284%29%5E2)
![K.E=11200\ J](https://tex.z-dn.net/?f=K.E%3D11200%5C%20J)
Therefore, The first car has 18750 J kinetic energy.
Hence, The first car has the most kinetic energy.