To solve this problem it is necessary to apply the law of Malus which describes the change in the Intensity of Light when it crosses a polarized surface.
Mathematically the expression is given as
![I = I_0 cos^2\theta](https://tex.z-dn.net/?f=I%20%3D%20I_0%20cos%5E2%5Ctheta)
Where,
= Initial Intensity
I = Final Intensity after pass through the polarizer
= Angle between the polarizer and the light
Since it is sought to reduce the intensity by half the relationship between the two intensities will be given as
![\frac{I}{I_0} = \frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7BI%7D%7BI_0%7D%20%3D%20%5Cfrac%7B1%7D%7B2%7D)
Using the Malus Law we have,
![I = I_0 cos^2\theta](https://tex.z-dn.net/?f=I%20%3D%20I_0%20cos%5E2%5Ctheta)
![cos^2\theta = \frac{I}{I_0}](https://tex.z-dn.net/?f=cos%5E2%5Ctheta%20%3D%20%5Cfrac%7BI%7D%7BI_0%7D)
![cos^2\theta = \frac{1}{2}](https://tex.z-dn.net/?f=cos%5E2%5Ctheta%20%3D%20%5Cfrac%7B1%7D%7B2%7D)
![\theta = cos^{-1}(\frac{1}{2})^2](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20cos%5E%7B-1%7D%28%5Cfrac%7B1%7D%7B2%7D%29%5E2)
![\theta = 75.52\°](https://tex.z-dn.net/?f=%5Ctheta%20%3D%2075.52%5C%C2%B0)
Angle with respect to maximum is ![90-75.52 = 14.48\°](https://tex.z-dn.net/?f=90-75.52%20%3D%2014.48%5C%C2%B0)
Uhhh I’m not really sure of the answer i think it’s stratosphere
Answer:
e)
Explanation:
In an RC series circuit, at any time, the sum of the voltages through the resistor and the capacitor must be constant and equal to the voltage of the DC voltage source, in order to be compliant with KVL.
At= 0, as the voltage through the capacitor can't change instantaneously, all the voltage appears through the resistor, which means that a current flows, that begins to charge the capacitor, up to a point that the voltage through the capacitor is exactly equal to the DC voltage, so no current flows in the circuit anymore, and the charge in the capacitor reaches to its maximum value.
Answer:
c) Both the parts will weigh the same
Explanation:
center of gravity is based on weight so if you cut down the center of gravity you would have 2 equal parts
(might be D if it is cutting against the center of gravity)