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2 years ago

Look at the picture below thank you

Mathematics

2 answers:

MakcuM [25]2 years ago

8 0

Answer:

a. ratio of side length to perimeter 1:4

b. ratio of perimeter to side length 4:1

c. ratio of radius to diameter 1:2

d. ratio of diameter to radius 2:1

e. ratio of people to tables 5:1

f. ratio of tables to people 1:5

Illusion [34]2 years ago

3 0

Ratio of side length to perimeter 1:4
ratio of perimeter to side length 4:1
ratio of radius to diameter 1:2
ratio of diameter to radius 2:1
ratio of people to tables 5:1
ratio of tables to people 1:5

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Does the number 65/13 have a finite or an infinite decimal expansion?

SpyIntel [72]

Finite

because 65/13=5

6 0

3 years ago

If two lines are perpendicular to each other their slopes are

Anarel [89]

Positive slope and negative slope so one line is negative and the other is positive

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3 years ago

Ella wanted to order candy online.company A is offering 2 2/4 pounds of chocolate for $32.50 while company B is offering 2 3/4 p

lubasha [3.4K]

Answer:

Company B

Step-by-step explanation:

Company A is offering 2.5 pounds of chocolate in $32.5 while Company B is offering 2.75 pounds of chocolate in the same price

Per pound of company A=32.5/2.5

Company A per pound=$13

Per pound of company B=32.5/2.75

B=$11.8

Hence company B is offering the lowest price per pound

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3 years ago

Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of

Law Incorporation [45]

Answer:

Step-by-step explanation:

To solve this problem, we will use the following two theorems/definitions:

- Given a vector field F of the form (P(x,y,z),Q(x,y,z),W(x,y,z)) then the divergence of F denoted by $\nabla \cdot F = \frac{\partial P}{\partial x}+\frac{\partial Q}{\partial y}}+\frac{\partial W}{\partial z}$

- (Gauss' theorem)Given a closed surface S, the following applies

$\int_{S} F\cdot \vec{n} dS = \int_{V} \nabla \cdot F dV$

where n is the normal vector pointing outward of the surface and V is the volume bounded by the surface S.

Let us, in our case, calculate the divergence of the given field. We have that

$\nabla \cdot F = \frac{\partial}{\partial x}(x)+\frac{\partial}{\partial y}(2y)+ \frac{\partial}{\partial z}(5z) = 1+2+5 = 8$

Hence, by the Gauss theorem we have that

$\int_{S} F\cdot \vec{n} dS = \int_{V} 8 dV = 8\cdot\text{Volume of V}$

So, we must calculate the volume V bounded by the cube S.

We know that the vertices are located on the given points. We must determine the lenght of the side of the cube. To do so, we will take two vertices that are on the some side and whose coordinates differ in only one coordinate. Then, we will calculate the distance between the vertices and that is the lenght of the side.

Take the vertices (1,1,1) and (1,1-1). The distance between them is given by

$\sqrt[]{(1-1)^2+(1-1)^2+(1-(-1)^2} = \sqrt[]{4} = 2$ .