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2 years ago

7

To help their patients, psychologists seek to control them, that is, to make the

1 answer:

dsp732 years ago

7 0

Answer: true

Step-by-step explanation:

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AB is included between--------

nirvana33 [79]

Answer:

B) ∠A and ∠B

Step-by-step explanation:

AB is the line segment formed with endpoints at A and B. This means it lies between the angle with vertex at A, ∠A, and the angle with vertex at B, ∠B.

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3 years ago

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Six different second-year medical students at Bellevue Hospital measured the blood pressure of the same person. The systolic re

Sauron [17]

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What? Hey no no no yes what no no yes what yes yes

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3 years ago

Solve for X 68=-52x+16

dimulka [17.4K]

Answer:

-1

Step-by-step explanation:

Move the +16 onto the other side. We now have 52 = -52x. Divide each side by 54 to get x = -1.

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2 years ago

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The perimiter of each face of a rubiks cube is 22.2 centimeters. What is the length of and edge of the rubiks cube?

ivanzaharov [21]

Answer:

3.7 cm

Step-by-step explanation:

22.2 / 6 = 2.7

Hope that helps!

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3 years ago

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

astra-53 [7]

Answer:

$3\pi \rightarrow y=2\cos \dfrac{2x}{3}\\ \\\dfrac{2\pi }{3}\rightarrow y=6\sin 3x\\ \\\dfrac{\pi }{3}\rightarrow y=-3\tan 3x\\ \\10\pi \rightarrow y=-\dfrac{2}{3}\sec \dfrac{x}{5}$

Step-by-step explanation:

The period of the functions $y=a\cos(bx+c)$ , $y=a\sin(bx+c)$ , $y=a\sec (bx+c)$ or $y=a\csc(bx+c)$ can be calculated as

$T=\dfrac{2\pi}{b}$

The period of the functions $y=a\tan(bx+c)$ or $y=a\cot(bx+c)$ can be calculated as

$T=\dfrac{\pi}{b}$

A. The period of the function $y=-3\tan 3x$ is

$T=\dfrac{\pi}{3}$

B. The period of the function $y=6\sin 3x$ is

$T=\dfrac{2\pi}{3}$

C. The period of the function $y=-4\cot \dfrac{x}{4}$ is

$T=\dfrac{\pi}{\frac{1}{4}}=4\pi$

D. The period of the function $y=2\cos \dfrac{2x}{3}$ is

$T=\dfrac{2\pi}{\frac{2}{3}}=3\pi$

E. The period of the function $y=-\dfrac{2}{3}\sec \dfrac{x}{5}$ is

$T=\dfrac{2\pi}{\frac{1}{5}}=10\pi$

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3 years ago