The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more variables and numbers.
Let w represent the width, hence:
length = w + 33, height = w - 13
Volume (V) = w(w + 33)(w - 13) = w³ + 20w² - 429w
V(w) = w³ + 20w² - 429w
Rate of change = dV/dw = 3w² + 40w - 429
When w = 38, dV/dw = 3(38)² + 40(38) - 429 = 5423
When w = 53, dV/dw = 3(53)² + 40(53) - 429 = 10118
Rate = 10118 - 5423 = 4695 in³/in
The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in
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270,000 is the answer because you have three over 100 so you do 100 divided by three which give you 0.15 then you do 120,000 times 0.15 to find out how much it grows per year to get 18,000 then you multiply 18’000 by 15 and get 270’000
Answer:
40 lbs was used
Step-by-step explanation:
If there is 20% left, that means 80% was used
50 *80%
Change to decimal form
50 *.80
40
40 lbs was used
