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3 years ago

What is the period of a pendulum that takes 3 seconds to move forward, and another 3 seconds to come back?

Physics

1 answer:

Serga [27]3 years ago

5 0

The period of the pendulum is 6 seconds.

<h3>What is period?</h3>

Period is the time taken for a simple pendulum to move to(forward) and fro(backward). The s.i unit of period is seconds(s).

Note: When a simple pendulum moves to and fro. it completes one cycle.

From the question, The period of the pendulum is calculated using the formula below.

<h3>Formula</h3>

T = a+b.............. Equation 1

Where:

T = Period of the pendulum
a = Time taken for the pendulum to move forward
b = Time taken for the pendulum to move backward.

From the question,

Given:

a = 3 seconds
b = seconds

Substitute the values above into equation 1

T = 3+3
T = 6 seconds.

Hence, The period of the pendulum is 6 seconds.

Learn more about period here: brainly.com/question/21924087

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VMariaS [17]

Answer:

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Explanation:

So, from the question, we are given that the charge = q, the momentum = p.

=> From the question We are also given that, "initially, there is movement along the x-axis which then enters a region where a uniform magnetic field* B = (B0)(k) which then extends over a width x = L, the distance = d in the +y direction as it traverses the field."

Momentum,P = mass × Velocity, v -----(1).

We know that for a free particle the magnetic field is equal to the centrepetal force. Thus, we have the magnetic field = mass,.m × (velocity,v)^2 / radius, r.

Radius,r = P × v / B0 -----------------------------(2).

Centrepetal force = q × B0 × v. ----------(3).

(If X = L and distance = d)Therefore, the radius after solving binomially, radius = (d^2 + 2 L^2) / 2d.

Equating Equation (2) and (3) gives;

P = B0 × q × r.

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3 years ago

A solid sphere of radius R is made of an insulating material. It holds a charge, Q, which is distributed evenly throughout the s

Vinvika [58]

Answer:

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Explanation:

Given:

Radius of the solid sphere=R
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Now using Gauss Law we have

$E\times4\pi r^2=\dfrac{q_{in}}{\epsilon_0}\\E\times4\pi r^2=\dfrac{\dfrac{Qr^3}{R^3}}{\epsilon_0}\\E=\dfrac{Qr}{4\pi \epsilon_0 R^3}$

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Answer:

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= V ( secondary ) x current ( secondary )

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Some Physics questions! Please help!

lesantik [10]

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$v_y = v sin \theta$

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