Recall that the blocks can only move along the x axis. The x components of their velocities at a certain moment are v1x and v2x.
Find the x component of the velocity of the center of mass (vcm)x at that moment. Keep in mind that, in general: vx=dx/dt.
1 answer:
Answer: Vcm = m1v1 + m2v2 / m1 + m2
Explanation:
The distance of centre of mass Xcm can be taken by taking mass moments about the origin.
(m1 + m2)Xcg = m1x1 + m2x2
Xcm = m1x1 + m2x2 / m1 + m2
Differentiating Xcm = m1x1 + m2x2 / m1 + m2 with respect to time t, will give us the velocity of the centre of mass.
I have attached a diagram showing said differentiation.
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Answer:
p = 6.64 cm
Explanation:
For this exercise we use the equation of the constructor
where f is the focal length, p and q are the distance to the object and the image, respectively
They tell us the focal length f = 2.2 cm and that the image as far as it can go is q = 3.29 cm, let's find the position of the object that creates this image
1 / p = 1 / 2.2 - 1/3.29
1 / p = 0.15059
p = 6.64 cm
therefore the farthest distance from the object is 6.64 c