Recall that the blocks can only move along the x axis. The x components of their velocities at a certain moment are v1x and v2x.
Find the x component of the velocity of the center of mass (vcm)x at that moment. Keep in mind that, in general: vx=dx/dt.
1 answer:
Answer: Vcm = m1v1 + m2v2 / m1 + m2
Explanation:
The distance of centre of mass Xcm can be taken by taking mass moments about the origin.
(m1 + m2)Xcg = m1x1 + m2x2
Xcm = m1x1 + m2x2 / m1 + m2
Differentiating Xcm = m1x1 + m2x2 / m1 + m2 with respect to time t, will give us the velocity of the centre of mass.
I have attached a diagram showing said differentiation.
You might be interested in
a. 46 m/s east
The jet here is moving with a uniform accelerated motion, so we can use the following suvat equation to find its velocity:
where
v is the velocity calculated at time t
u is the initial velocity
a is the acceleration
The jet in the problem has, taking east as positive direction:
u = +16 m/s is the initial velocity
is the acceleration
Substituting t = 10 s, we find the final velocity of the jet:
And since the result is positive, the direction is east.
b. 310 m
The displacement of the jet can be found using another suvat equation
where
s is the displacement
u is the initial velocity
a is the acceleration
t is the time
For the jet in this problem,
u = +16 m/s is the initial velocity
is the acceleration
t = 10 s is the time
Substituting into the equation,