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Shkiper50 [21]
2 years ago
10

A transformer connected to a 110–(V) (rms) ac line is to supply 10.0 (V) (rms) to a portable electronic device. The load resista

nce R in the secondary is 6.00 N.
(a) (2 points) What should the ratio of secondary to primary turns of the transformer be? Note: "Secondary" refers the portable device's load and "primary" refers to the ac-line.

(b) (2 points) What rms current I, must the secondary supply to the load?

(c) (2 points) What average power is delivered to the load?

(d) (2 points) Based on your answer to (c), what is the average power I,*V1 delivered by the ac-line? Hint: Use conservation of energy.

(e) (2 points) What is the current I, drawn by the ac line?

(f) (6 points) what is the effect resistance Rer?
Physics
1 answer:
spayn [35]2 years ago
5 0

Answer:

Explanation:

a ) V( primary ) = 100 V

V( secondary ) = 10 V

No of turns ( secondary ) / No of turns ( primary ) = 10 / 100

= 1 / 10

b ) current in secondary

= volt ( secondary ) / resistance

= 10 /6 = 1.67 A

c )

Average power to secondary

= V  ( secondary ) x current ( secondary )

= 10 x 10 / 6

= 16.67 W

d )

Power in primary = power in secondary = 16.67 W

e ) current drawn by ac line ( primary )

Volt ( primary ) x current ( primary ) = power in primary

= 16.67

current ( primary )

= 16.67 / 100

= 0.167 A

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In his famous experiment, Rutherford fired alpha particles at a thin gold film. Most of the alpha particles went through the fir
ale4655 [162]

Answer:

1. The nucleus is about 1/2 the size of the atom

Explanation:

Alpha particles are positive charge particles and they are bounced back by the nucleus because nucleus is also same size

Now in present experiment Rutherford found that very few alpha particles are bounced back along same path which shows that very small region inside the nucleus is having positive charge and rest part of the atom is empty.

Now if we found that half of the alpha particles are bounced back then it shows that size of the nucleus is very large now as compare to previous one because only nucleus can bounce back the alpha particles

so correct answer will be

1. The nucleus is about 1/2 the size of the atom

5 0
3 years ago
WILL MARK THE BRAINLIEST <br> pls help
il63 [147K]

Answer:

I think B but im not sure

Explanation:

3 0
2 years ago
Read 2 more answers
2013 Indianapolis 500 champion Tony Kanaan holds his hand out of his IndyCar while driving through still air with standard atmos
Citrus2011 [14]

Answer:

(a). The pressure is 14.76 psi.

(b). The pressure is 15.59 psi.

(c). The pressure is 15.68 psi.

All answer are reasonable.

Explanation:

Given that,

Speed v₁= 60 mph

Speed v₂ = 225 mph

Speed v₃ = 235 mph

(a). We need to calculate the maximum pressure on his hand

Using equation of pressure

P_{1}=P+\dfrac{1}{2}\rho v^2+\rho gh

there, no vertical movement

So, on neglect of height term

P_{1}=P+\dfrac{1}{2}\rho v_{1}^2

Where, P= atmospheric pressure

\rho = air density

v = speed

Put the value in the equation

P_{1}=14.7\times144+\dfrac{1}{2}\times(0.002376\times(60\times1.4667)^2)

P_{1}=2126.0\ lb/ft^2

P_{1}=\dfrac{2126.0}{144}

P_{1}= 14.76\ psi

(b). Speed v₂ = 225 mph

We need to calculate the maximum pressure on his hand

Using equation of pressure

P_{2}=P+\dfrac{1}{2}\rho v_{2}^2

Put the value in the equation

P_{2}=14.7\times144+\dfrac{1}{2}\times(0.002376\times(225\times1.4667)^2)

P_{2}=2246.17\ lb/ft^2

P_{2}=\dfrac{2246.17}{144}

P_{2}= 15.59\ psi

(c).  Speed v₃ = 235 mph

We need to calculate the maximum pressure on his hand

Using equation of pressure

P_{3}=P+\dfrac{1}{2}\rho v_{3}^2

Put the value in the equation

P_{3}=14.7\times144+\dfrac{1}{2}\times(0.002376\times(235\times1.4667)^2)

P_{3}=2257.93\ lb/ft^2

P_{3}=\dfrac{2257.93}{144}

P_{3}= 15.68\ psi

According to bernoulli's equation,

If the car increases the velocity the the pressure on the surface of the driver's hand increases.

The pressure from P₁ to P₃ are all near the value of one atmosphere.

So, the pressure difference of one atmosphere is not enough to break the driver's hand.

Hence, (a). The pressure is 14.76 psi.

(b). The pressure is 15.59 psi.

(c). The pressure is 15.68 psi.

All answer are reasonable.

5 0
3 years ago
If the tension in the rope is 160 n, how much work does the rope do on the skier during a forward displacement of 270 m?
Lunna [17]

If the tension in the rope is 160 n, - 43200 J work doen by the rope on the skier during a forward displacement of 270 m.

Given,

Tension force in the rope is (T) = 160 N

Displacement of the skier (S) = 270 m

The displacement takes place in forward direction while the direction of the tension in the rope is opposite to it.

Therefore, work done by the rope on  the skier is,

   W=T.S

⇒W=270*160*cos\pi \\W=-43200 J

Hence work done by the rope is - 43200 J.

Learn more about force problems on

brainly.com/question/26850893

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8 0
2 years ago
Read 2 more answers
When the switch is closed, what happens to the current in the circuit? (The intrinsic resistance of the inductor is zero.)
Hitman42 [59]
The best and most correct answer among the choices provided by your question is the second choice or letter B.

<span>When the switch is closed, the current instantaneously becomes 1.</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
6 0
3 years ago
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