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jolli1 [7]
2 years ago
10

What is an extended structure? How do extended structures make up substances

Chemistry
1 answer:
Novosadov [1.4K]2 years ago
8 0
46 because the formal is a expression
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This is the chemical formula for acetic acid (the chemical that gives the sharp taste to vinegar): An analytical chemist has det
murzikaleks [220]

Answer:

0.11 mol

Explanation:

<em>This is the chemical formula for acetic acid (the chemical that gives the sharp taste to vinegar): CH₃CO₂H. An analytical chemist has determined by measurements that there are 0.054 moles of oxygen in a sample of acetic acid. How many moles of hydrogen are in the sample?</em>

Step 1: Given data

  • Formula of acetic acid: CH₃CO₂H
  • Moles of oxygen in the sample of acetic acid: 0.054 moles

Step 2: Establish the appropriate molar ratio

According to the chemical formula of acetic acid, the molar ratio of H to O is 4:2.

Step 3: Calculate the moles of atoms of hydrogen

We will use the theoretical molar ratio for acetic acid.

0.054 mol O × (4 mol H/2 mol O) = 0.11 mol H

3 0
3 years ago
If I add 475mL of water to 75.0mL of a 0.315M NaOH solution, what will the molarity of the diluted solution be?
pantera1 [17]
Answer is: <span>the molarity of the diluted solution 0,043 M.
</span>V(NaOH) = 75 mL ÷ 1000 mL/L = 0,075 L.
c(NaOH) = 0,315 M = 0,315 mol/L.
n(NaOH) = c(NaOH) · V(NaOH).
n(NaOH) = 0,075 L · 0,315 mol/L.
n(NaOH) = 0,023625 mol.
V(solution) = 0,475 L + 0,75 L.
c(solution) = 0,023625 mol ÷ 0,550 L.
c(solution) = 0,043 mol/L.
5 0
3 years ago
What is the molarity of a KF(aq) solution containing 3.0 mol of KF in 2.00L of solution?
sergeinik [125]

Answer : The molarity of KF in the solution is 1.5 M.

Explanation : Given,

Moles of KF = 3.0 mol

Volume of solution = 2.00 L

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

\text{Molarity}=\frac{\text{Moles of }KF}{\text{Volume of solution (in L)}}

Now put all the given values in this formula, we get:

\text{Molarity}=\frac{3.0mol}{2.00L}=1.5mole/L=1.5M

Therefore, the molarity of KF in the solution is 1.5 M.

4 0
3 years ago
CAN SOMEONE PLEASE HELP ME?!
Len [333]

Answer:

no

Explanation:

because

5 0
3 years ago
What is ksp for agi, if its molar solubility is 9.1 × 10−9 mol/l?
LekaFEV [45]
When the salt AgI dissolves, it dissociates as follows;
AgI --> Ag⁺ + I⁻
molar solubility of salt is the amount of salt that can be dissolved in 1 L of solution
since the ions dissociated are in 1:1 molar ratio, the molar solubility of the ions are equivalent to the molar solubility of the salt.
ksp is the solubility product constant of the salt
ksp = [Ag⁺][I⁻]
ksp = (9.1 x 10⁻⁹ mol/L)²
ksp = 8.28 x 10⁻¹⁷
4 0
3 years ago
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