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jolli1 [7]
2 years ago
10

What is an extended structure? How do extended structures make up substances

Chemistry
1 answer:
Novosadov [1.4K]2 years ago
8 0
46 because the formal is a expression
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"in the cores of extremely hot red giants, nuclear reactions convert helium to ____.
Sergeu [11.5K]

Red giants produce "metals", i.e., heavier elements.

The first step is helium conversion into

<span>carbon</span>

6 0
3 years ago
How many grams of iron are needed to combine with 24.9 g of 0 to make Fe203?
Pavlova-9 [17]

Answer:

Explanation:

Here's where all that equation balancing is going to come into use. Since the main object of the question is not the equation, I'm just going to balance it and use it.

4Fe + 3O2 ====> 2Fe2O3

Step One

Find the number of mols of O2 in 24.9 grams of O2

1 mol O2 = 2*16 = 32 grams

x mol O2 = 24.9 grams               Cross multiply

32x = 24.9 * 1                               Divide by 32

x = 24.9/32

x = 0.778 moles of O2

Step Two

Type the findings under the balanced equations parts. Solve for the number of moles of Fe

4Fe + 3O2 ====> 2Fe2O3

x          0.778

Step Three

Set up the proportion

4/x = 3/0.778            Cross multiply

Step Four

Solve the proportion moles of Fe

4*0.778 = 3x              

3.112   =    3x                      Divide by 3

3.112/3 = 3x/3

x = 1.037 moles of Fe

Step Five

Find the mass of Fe

1 mol Fe = 56 grams

1.037 mol Fe = x            Cross Multiply

x = 56*1.037

x = 58.1 grams

4 0
3 years ago
What are two methods to solve the energy crisis?​
grin007 [14]

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4 0
3 years ago
Caffeine, a stimulant found in coffee and soda, hasthe mass percent composition: C. 49.48%, H, 5.19%. N. 28.85% 0. 16.48% The mo
borishaifa [10]

We have the next % composition:

C. 49.48%

H, 5.19%.

N. 28.85%

0. 16.48%

We assume 100 g of sample

1) As we have 100 g of sample of Caffeine, we calculate the mass of each element involved here.

C. 49.48 g

H, 5.19 g

N. 28.85 g

0. 16.48 g

2) We calculate the number of moles of each element (we need the mass per mole of each element)

For C) 12.01 g/mol

49.48 g x (1 mol/12.01 g) = 4.120 moles

For H) 1.007 g/mol

5.19 g x (1 mol/1.007 g) = 5.154 moles

For O) 15.99 g/mol

16.48 g x (1 mol/15.99 g) = 1.030 moles

For N) 14.00 g/mol

28.85 g x (1 mol/14.00 g) = 2.060 moles

3) We choose the smallest number from 2) and divide the rest of them by it.

For C) 4.120 moles/1.030 moles= 4

For H) 5.154 moles/1.030 moles= 5

For O) 1.030 moles/1.030 moles= 1

For N) 2.060 moles/1.030 moles= 2

4) The numbers in 3) represents the subindex from the empirical formula of caffeine:

C_4H_5O_1N_2

5) We calculate the molar mass of our empirical formula, 97.06 g/mol.

We already have the molar mass of the molecular formula, so we proceed like this:

n= the molar mass of the molecular formula/the molar mass of the empirical formula

n = 194.19 g/mol/97.06 g/mol = 2 approx.

We use "n" and we multiply our empirical formula by n = 2:

Therefore, our molecular formula:

C_8H_{10}O_2N_4

8 0
1 year ago
Write a hypothesis about the use of an object physical characteristics to determine its density use the format if then because a
Snowcat [4.5K]

Answer:density of an object can be determined by the total mass and buoyancy of the object

Explanation:

6 0
2 years ago
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