I NEED THIS LESS THAN 7 MINUTES IYS 15 POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! What is the difference betwe
2 answers:
You might be interested in
Answer : The molecular formula of a compound is,
Solution : Given,
Mass of C = 64.03 g
Mass of H = 4.48 g
Mass of Cl = 31.49 g
Molar mass of C = 12 g/mole
Molar mass of H = 1 g/mole
Molar mass of Cl = 35.5 g/mole
Step 1 : convert given masses into moles.
Moles of C =
Moles of H =
Moles of Cl =
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C =
For H =
For Cl =
The ratio of C : H : Cl = 6 : 5 : 1
The mole ratio of the element is represented by subscripts in empirical formula.
The Empirical formula =
The empirical formula weight = 6(12) + 5(1) + 1(35.5) = 112.5 gram/eq
Now we have to calculate the molecular formula of the compound.
Formula used :
Molecular formula =
Therefore, the molecular of the compound is,
Answer:
Compound B.
Explanation:
The freezing point depression is a colligative property. It depends on the number of particles (moles) present in the solution.
where b is the molal concentration
If m is constant (5 g), then
The compound with the greater molar mass has fewer moles and therefore fewer particles to depress the freezing point.
That must be Compound B, because Compound A has the lower freezing point.
Answer:
-537.25 kJ/mol is the standard enthalpy of formation of solid glycine.
Explanation:
Standard enthalpy of formation of oxygen gas=
Standard enthalpy of formation of carbon dioxide=
Standard enthalpy of formation of water =
Standard enthalpy of formation of nitrogen gas=
Standard enthalpy of formation of glycine =
Enthalpy of the reaction =
=
On rearranging :
-537.25 kJ/mol is the standard enthalpy of formation of solid glycine.