Answer:
Basically, paramagnetic and diamagnetic refer to the way a chemical species interacts with a magnetic field. More specifically, it refers to whether or not a chemical species has any unpaired electrons or not.
A diamagnetic species has no unpaired electrons, while a paramagnetic species has one or more unpaired electrons.
Now, I won't go into too much detail about crystal field theory in general, since I assume that you're familiar with it.
So, you're dealing with the hexafluorocobaltate(III) ion, [CoF6]3â’, and the hexacyanocobaltate(III) ion, [Co(CN)6]3â’.
You know that [CoF6]3â’ is paramagnetic and that [Co(CN)6]3â’ is diamagnetic, which means that you're going to have to determine why the former ion has unpaired electrons and the latter does not.
Both complex ions contain the cobalt(III) cation, Co3+, which has the following electron configuration
Co3+:1s22s22p63s23p63d6
For an isolated cobalt(III) cation, all these five 3d-orbitals are degenerate. The thing to remember now is that the position of the ligand on the spectrochemical series will determine how these d-orbtals will split.
More specifically, you can say that
a strong field ligand will produce a more significant splitting energy, Δ a weak field ligand will produce a less significant splitting energy, Δ
Now, the spectrochemical series looks like this
http://chemedu.pu.edu.tw/genchem/delement/9.htmhttp://chemedu.pu.edu.tw/genchem/delement/9.htm
Notice that the cyanide ion, CNâ’, is higher on the spectrochemical series than the fluoride ion, Fâ’. This means that the cyanide ion ligands will cause a more significant energy gap between the eg and t2g orbitals when compared with the fluoride ion ligands.
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In the case of the hexafluorocobaltate(III) ion, the splitting energy is smaller than the electron pairing energy, and so it is energetically favorable to promote two electrons from the t2g orbitals to the eg orbitals → a high spin complex will be formed.
This will ensure that the hexafluorocobaltate(III) ion will have unpaired electrons, and thus be paramagnetic.
On the other hand, in the case of the hexacyanocobaltate(III) ion, the splitting energy is higher than the electron pairing energy, and so it is energetically favorable to pair up those four electrons in the t2g orbitals → a low spin complex is formed.
Since it has no unpaired electrons, the hexacyanocobaltate(III) ion will be diamagnetic.
Answer:
Beta rays are electrons.
Explanation:
A neutron in the nucleus of a radioactive atom decays into a proton and an electron, which is emitted from the atom.
Answer:
A) M = 100X
B) M = 36X
C) M = 178.88X
Explanation:
Given data:
ASTM grain size number 7
a) total grain per inch^2 - 64 grain/inch^2
we know that number of grain per square inch is given as
where M is magnification, n is grain size
therefore we have
solving for M we get
M = 100 X
B) total grain per inch^2 = 500 grain/inch^2
we know that number of grain per square inch is given as
where M is magnification, n is grain size
therefore we have
solving for M we get
M = 36 X
C) Total grain per inch^2 = 20 grain/inch^2
we know that number of grain per square inch is given as
where M is magnification, n is grain size
therefore we have
solving for M we get
M = 178.88 X
Because the coldness in the ice cream and the suns gamma rays are hitting the ice cream and then it will start to melt. and that is why ice cream melts.
Part 1:
The process that arrow C signifies is the burning of fossil fuels in order to present carbon dioxide into the atmosphere. The mentioned procedure in the carbon cycle is comparatively new as humans were not able to generate huge concentrations of carbon dioxide by burning fossil fuels until the emergence of the Industrial revolution.
Part 2:
The phenomenon, which could discharge the compound into the air is the burning of fuels. It is an oxidation reaction in which the carbon present in the hydrocarbons in the fuel is oxidized to carbon dioxide by the presence of oxygen in the air. The carbon dioxide discharged into the atmosphere contributes to the greenhouse effect.
Part 3:
The elements, which produce it are conserved at the time of the carbon cycle by the Law of Conservation of Matter. According to this law, the matter is neither consumed nor produced, it only gets transformed. So, at the time of chemical procedures in the carbon cycle, the atoms of carbon are never destructed, however, they get rearrange and modify into distinct molecules. The mentioned cycle is essential for maintaining life on Earth.
