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Step2247 [10]
2 years ago
11

1q

Chemistry
1 answer:
Lena [83]2 years ago
3 0

Answer:

I am not sure what was the passage but the relationship between clownfish and sea anemone is mutualism where they both benefit each other.

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What passes through the Haversian canal
Tamiku [17]

A Haversian canal is referred to as any minute tube, which forms a network in a bone and also contains blood vessels. Blood vessels, nerve fibers and lymphatics may pass through the Haversian canal. Haversian canals are found surrounding blood vessels and nerve cells all over the bones and interacts with bone cells from end to end networks known as canaliculi.

4 0
3 years ago
Elements are organized into groups / families according to their physical and chemical properties. Identify the elements that's
Kryger [21]

Answer:

1 valence - Alkali Metals: Li Lithium, Na Sodium, K Potassium

2 valence - Alkaline Earth Metals: Be Beryllium, Mg Magnesium, Ca Calcium

3 valence - Non-metals: B Boron, Al Aluminium

4 valence - Non-metals: C Carbon, Si Silicon

5 valence - Non-metals: N Nitrogen, P Phosphorus

6 valence - Non-metals: O Oxygen, S Sulfur, Se Selenium

7 valence - Halogens: F Fluorine, Cl Chlorine, Br Bromine

8 valence - Noble Gases: He Helium, Ne Neon, Ar Argon

3 0
4 years ago
If the pOH of a nitric acid (HNO3) solution is measured as 11, what is the concentration of HNO3 solution?
Illusion [34]

1 gram of HNO3 will be equal to 1/63.01 moles. Therefore, we can say that 1 liter of Nitric acid contains 15.6976 moles or in other words molarity of 70% (w/w) Nitric acid is equal to 15.6976 M.

Known values  

Molecular weight of HNO3 63.01 g/mole

Concentration of Nitric acid 70% (% by mass, wt/wt)

4 0
2 years ago
If 1.00 g of a hydrocarbon is combusted and found to produce 3.14 g of co2, what is the empirical formula of the hydrocarbon?
photoshop1234 [79]
The combustion reaction is as expressed,

                CxHy + O2 --> CO2 + H2O

The mass fraction of carbon in CO2 is 3/11. Hence,
       mass of C in CO2 = (3.14 g)(3/11) = 0.86 g C.

Given that we have 1 g of the hydrocarbon, the mass of H is equal to 0.14 g. 

     moles of C = 0.86 g C / 12 g = 0.0713
     moles of H = 0.14 g H / 1 g  = 0.14

The empirical formula for the hydrocarbon is therefore, CH₂.
7 0
3 years ago
Let the simulator run for 30 seconds. What happens to the size of the ice?
Shkiper50 [21]

  1. 10 is your answer hope it helps you.......... Xd
<h2>Answer : 10 </h2>
7 0
3 years ago
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