<h3><u>Answer;</u></h3>
= 49.42 g
<h3><u>Explanation;</u></h3>
The equation for the reaction between Lead (ii) nitrate and sodium iodide;
Pb(NO3)2(aq) + 2 NaI(aq) ---> 2NaNO3(aq) + PbI2(s)
The precipitate formed in this equation is Lead iodide
We first calculate the moles of lead nitrate;
Moles = mass/molar mass
= 35.5 g/ 331.2 g/mol
= 0.1072 moles
The mole ratio of Pb(NO3)2 : PbI2 is 1 : 1
Therefore; the number of moles of lead iodide is 0.1072 moles
Mass = moles × molar mass
= 0.1072 moles × 461.01 g/mol
<u>= 49.42 g</u>
D) warm and wet.
Water can be a catalyst, and heat speeds up reactions.
Answer:
Acid-base indicators are generally weak proteolytic that change color in solution according to the pH. The acid-base equilibrium of a weak acid type of indicator (HI) in water can be represented as. [I] The acid, HI, and the conjugate base, I−, have different colors. The equilibrium expression for this process is.
Is the following reaction spontaneous at 298 K? Answer by calculating ΔG. H2O(g) + C(s) → CO(g) + H2(g) ΔH = 131.3 kJ/mole ΔS = 134 J/mole˙K
No
Explanation:
i think its B but i'm not fully sure (Correct)
