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Paraphin [41]
2 years ago
8

Can you help me!!!!!!!!

Mathematics
1 answer:
Citrus2011 [14]2 years ago
6 0

Answer:

Yes, this is A Linear Function!

Step-by-step explanation:

This is a linear function beacuse linear functions are straight lines on the graph as you may know. So when we graph these numbers it turns up as a straight increasing linear line.

(I attached a pic for u)


Hope this helps!

<3 me if it did!

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Stans steak house has a server to cook ratio of 5 to 2.The total number of servers and cooks is 42. How many servers does Stans
aivan3 [116]

Answer: 30 servers

5+2 = 7

42/7 = 6 sets of employees

5*6 = 30 servers

Step-by-step explanation:

5+2 = 7

42/7 = 6 sets of employees

5*6 = 30 servers

3 0
3 years ago
Select a setting so that each given point will lie within the viewing window.
NemiM [27]

Answer:

The given points are

(-13,3)\\(0,0)\\(-2,-7)

The setting would have a interval or 2 units above and below the minimum and maximum of each coordinate.

The given maxium horizontal coordinate is 0.

The given minimum horizontal coordinate is -13.

The given maximum vertical coordinate is 3.

The given minimum vertical coordinate is -7.

Now, we extend each maximum and minimum value by 2 units to create the setting.

So, the setting is

x_{min}=-15\\x_{max}=2\\ y_{min}=-9\\y_{max}=5

With a scale of 2 units.

6 0
3 years ago
Find maclaurin series
Mumz [18]

Recall the Maclaurin expansion for cos(x), valid for all real x :

\displaystyle \cos(x) = \sum_{n=0}^\infty (-1)^n \frac{x^{2n}}{(2n)!}

Then replacing x with √5 x (I'm assuming you mean √5 times x, and not √(5x)) gives

\displaystyle \cos\left(\sqrt 5\,x\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt5\,x\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^{2n}}{(2n)!}

The first 3 terms of the series are

\cos\left(\sqrt5\,x\right) \approx 1 - \dfrac{5x^2}2 + \dfrac{25x^4}{24}

and the general n-th term is as shown in the series.

In case you did mean cos(√(5x)), we would instead end up with

\displaystyle \cos\left(\sqrt{5x}\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt{5x}\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^n}{(2n)!}

which amounts to replacing the x with √x in the expansion of cos(√5 x) :

\cos\left(\sqrt{5x}\right) \approx 1 - \dfrac{5x}2 + \dfrac{25x^2}{24}

7 0
2 years ago
Solve the equation 3y-9x=-3
ipn [44]
This equation can have a number of solutions. Typically when solving a two-variable equation, you are looking for the slope intercept form of the line. In this case that is:

y = 3x - 1
7 0
3 years ago
Sam and Bethan share £54 in the ratio 5:4 how much dose each get
Agata [3.3K]
Ratio 5:4 
Total shares = 5+4 = 9

then to find for 1 share = 54/9 = 6

So Sam share = 6 x 5 = 30
Bethan share = 6 x 4 = 24

Poof: 30+24 = 54

3 0
3 years ago
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