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4 years ago

HURRY UP PLEASE !!

Mathematics

1 answer:

IRISSAK [1]4 years ago

7 0

Answer:

<h2>The x-interecepts are 5.6 and -1.4, approximately.</h2>

Step-by-step explanation:

The given equation is

$5x^{2} -21x=39$

Where $a=5$ , $b=-21$ and $c=39$ , let's use the quadratic formula

$x_{1,2}=\frac{-b(+-)\sqrt{b^{2}-4ac } }{2a} =\frac{-(-21) (+-)\sqrt{(-21)^{2} -4(5)(-39)} }{2(5)}\\ x_{1,2}=\frac{21(+-)\sqrt{441+780} }{10}=\frac{21(+-35)}{10}\\x_{1}=\frac{21+35}{10}=\frac{56}{10} \approx 5.6\\ x_{2}=\frac{21-35}{10}=\frac{-14}{10} \approx -1.4$

Therefore, the x-interecepts are 5.6 and -1.4, approximately.

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3 years ago

Wendy's mother recorded how many donuts she has eaten over the past few months. Jelly-filled donuts 6 maple donuts 53 glazed don

coldgirl [10]

Answer:

$P(\text{Powdered sugar donut})=\dfrac{1}{15}$ .

Step-by-step explanation:

It is given that Wendy's mother recorded how many donuts she has eaten over the past few months.

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Maple donuts = 53

Glazed donuts = 11

Powdered sugar donuts = 5

Now,

Total number of donuts = 6 + 53 + 11 + 5 = 75

We need to find the experimental probability that the next donut Wendy eats will be a powdered sugar donut.

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4 years ago

A company establishes a fund of 120 from which it wants to pay an amount,C, to any of its 20 employees who achieve a high-perfor

Leno4ka [110]

Answer:

$C=120/2=60$

Step by step Explanation'

To solve this problem, we will need to apply trial-and-error calculation with the binomial distribution, even though it appears like Central Limit Theorem but it's not.

For us to know the value of C , we will look for a minimum integer such that having 'n' number of high performance level of employee has the probability below 0.01.

Determine the maximum value of C, then the maximum value that C can have is 120/n

Let us represent X as the number of employees with high performance with a binomial distribution of

P =0.02( since the percentage of chance of achieving a high performance level is 2%)

n = 20 ( number of employees who achieve a high performance level)

The probability of X= 0 can be calculated

P( X= 0) = 0.98^n

$P(X=0)=0.98^20$

$P(X=0)=0.668$

$P(X=1)=0.02*20*0.98^19$

$P(X=1)=0.272$

$P(X=2)=0.02^2*20*0.98^18$

$P(X=2)=0.053$

Summation of P( X= 0)+ P( X= 1)+P( X= 2) will give us the value of 0.993 which is greater than 0.99( 1% that the fund will be inadequate to cover all payments for high performance.)

BUT the summation of P( X= 0)+ P( X= 1) will give the value of 0.94 which doesn't exceed the 0.99 value,

Therefore, the minimum value of integer in such a way that P(X >2) is less than 0.01 have n= 2

then the maximum value that C can have is 120/n

$C=120/2=60$

7 0

4 years ago