Question

HURRY UP PLEASE !!

Answer 1

Answer:

The x-interecepts are 5.6 and -1.4, approximately.

Step-by-step explanation:

The given equation is

$5x^{2} -21x=39$

Where $a=5$, $b=-21$ and $c=39$, let's use the quadratic formula

$x_{1,2}=\frac{-b(+-)\sqrt{b^{2}-4ac } }{2a} =\frac{-(-21) (+-)\sqrt{(-21)^{2} -4(5)(-39)} }{2(5)}\\ x_{1,2}=\frac{21(+-)\sqrt{441+780} }{10}=\frac{21(+-35)}{10}\\x_{1}=\frac{21+35}{10}=\frac{56}{10} \approx 5.6\\ x_{2}=\frac{21-35}{10}=\frac{-14}{10} \approx -1.4$

Therefore, the x-interecepts are 5.6 and -1.4, approximately.