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3 years ago

13

Leanne earned $400 and $550 in interest the last 2 years. How much interest must she earn this year so that her average earnings

over the three year period is more than $600?

1 answer:

polet [3.4K]3 years ago

3 0

Answer:

850

Step-by-step explanation:

400+550+850=1800. 1800/3= 600

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Skyler goes to a school which has 1000 students in it. She asks 40 random students whether they like the new 8.30am start to the

harina [27]

30/40 say no, so x/1000 would say no. 1000/40=25, 25*30=750. So, about 750 would dislike it.

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You are saving money to buy an electric guitar. You deposit $1000 in an account that earns interest compounded annually. The exp

Katena32 [7]

Let's move like a crab, backwards some.

after 2 years?

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$1000\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &2
\end{cases}
\\\\\\
A=1000\left(1+\frac{0.03}{1}\right)^{1\cdot 2}\implies A=1000(1.03)^2$

after 3 years?

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$1000\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &3
\end{cases}
\\\\\\
A=1000\left(1+\frac{0.03}{1}\right)^{1\cdot 3}\implies A=1000(1.03)^3$

is that enough to pay the $1100?

now, let's write 1000(1+r)² in standard form

1000( 1² + 2r + r²)

1000(1 + 2r + r²)

1000 + 2000r + 1000r²

1000r² + 2000r + 1000 <---- standard form.

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Answer:

d

Step-by-step explanation:

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3 years ago

What are the next 4 multiples of 4/8 in a fraction

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Answer:

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Step-by-step explanation:

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3 years ago

Dan's school is selling tickets to a play. On the first day of ticket sales the school sold 1 adult ticket and 6 student tickets

VashaNatasha [74]

Answer:

Let's define the variables:

A = price of one adult ticket.

S = price of one student ticket.

We know that:

"On the first day of ticket sales the school sold 1 adult ticket and 6 student tickets for a total of $69."

1*A + 6*S = $69

"The school took in $150 on the second day by selling 7 adult tickets and student tickets"

7*A + 7*S = $150

Then we have a system of equations:

A + 6*S = $69

7*A + 7*S = $150.

To solve this, we should start by isolating one variable in one of the equations, let's isolate A in the first equation:

A = $69 - 6*S

Now let's replace this in the other equation:

7*($69 - 6*S) + 7*S = $150

Now we can solve this for S.

$483 - 42*S + 7*S = $150

$483 - 35*S = $150

$483 - $150 = 35*S

$333 = 35*S

$333/35 = S

$9.51 = S

That we could round to $9.50

That is the price of one student ticket.

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2 years ago