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2 years ago

Find three consecutive integers whose sum is 0.

2 answers:

7 0

Let n=first number. So this means that the second number is n+2 and the third is n+4. Since the sum of the three numbers is 0, this means that

n+n+2+n+4=0

ANTONII [103]2 years ago

4 0

0, -3 ,+3

hope it helped u! ^^

You might be interested in

Determine the simple interest when:

ivann1987 [24]

Answer:

$75.65

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 4.25%/100 = 0.0425 per year,

then, solving our equation

I = 890 × 0.0425 × 2 = 75.65

I = $ 75.65

The simple interest accumulated

on a principal of $ 890.00

at a rate of 4.25% per year

for 2 years is $ 75.65.

4 0

3 years ago

algebraically determine the values of h and k to correctly complete the identity stated below : 2 x cubed - 10x squared + 11x -

11Alexandr11 [23.1K]

Answer:

The values for expression is h = - 2 and k = 5

Step-by-step explanation:

Given algebraic expression can be written as :

2 x³ - 10 x² + 11 x - 7 = ( x - 4 ) × ( 2 x² + h x + 3 ) + k

Now opening the bracket

Or, 2 x³ - 10 x² + 11 x - 7 = x × ( 2 x² + h x + 3 ) - 4 × ( 2 x² + h x + 3 ) + k

Or, 2 x³ - 10 x² + 11 x - 7 = 2 x³ + h x² + 3 x - 2 x² - 4 h x - 12 +k

Or , 2 x³ - 10 x² + 11 x - 7 = 2 x³ + ( h - 2 ) x² + ( 3 - 4 h ) x - 12 + k

Now, equating the equation both sides

I.e - 10 = ( h - 2 )

Or , h - 2 = - 10

I.e , h = - 10 + 2

∴ h = - 2

Again , 11 = ( 3 - 4 h )

or, 11 = 3 - 4 h

or, 11 - 3 = - 4 h

or, 8 = - 4 h

∴ h = $\frac{-8}{4}$

I.e h = - 2

Again

- 7 = - 12 + k

Or, k = - 7 + 12

∴ k = 5

Hence The values for expression is h = - 2 and k = 5 . Answer

5 0

3 years ago

What is the least common multiple of 8 and 11

tino4ka555 [31]

Answer:

Step-by-step explanation:

Find the prime factorization of both 8 and 11.

8 → 4 × 2 → 2 × 2 × 2

11 → 11

Then, multiply each factor the greater number of times it occurs. Since no factors are duplicated between 8 and 11 (as in, 2 is not a factor of 11, nor is 11 a factor of 8), LCM will equal 2 × 2 × 2 × 11.

2 × 2 × 2 × 11 = 88, so the LCM is 88.

It's a little hard to explain without visuals. A video could be useful, though I can't put links here.

7 0

3 years ago

Please help: linear algebra problem. (Linear combinations)

DochEvi [55]

Answer:

$\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right] \left[\begin{array}{ccc}c\\d\end{array}\right] =\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]$

This tells us that:

$A=\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right]$

$b=\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]$

Step-by-step explanation:

So we are saying we have scalars, c and d, such that:

$c\left[\begin{array}{ccc}5\\5\\ 3\end{array}\right]+d\left[\begin{array}{ccc}7\\-8\\-9\end{array}\right]=\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]$ .

So we want to find a way to express this as:

Ax=b where x is the scalar vector, $\left[\begin{array}{ccc}c\\d\end{array}\right]$ .

So we can write this as:

$\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right] \left[\begin{array}{ccc}c\\d\end{array}\right] =\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]$

3 0

3 years ago

The nutrition facts label on a container of dry roasted cashews indicates there are 161 calories in 28 grams. You eat 9 cashews

RoseWind [281]

Answer:

there are 161 calories in 28 gram,then:

one gram of dry roasted cashews contains=161/28=5.75 calories

You eat 12 gram of it, =12*5.75=69 calories

9 cashews has 12gram, then:

one gram of dry roasted cashews contains= 9/12 = 0.75 cashews

there are total of 28gram in one serving.

Therefore cashews in one serving = 0.75*28=21cashews

a)69 calories

b)21cashews

4 0

4 years ago