7,14,21,28,35,42,49,56,63,70,77,84,91,98,105,112,119,126
18,36,54,72,90,108,126
So the first person to get both of them is the 126th person
An=A1 r ^(n-1)
192= 3 r ^(4-1)
192 = 3 r^3
64 = r^3
r = 4
equation:
An=3 (4)^(n-1)
6th term:
An= 3 (4)^(6-1)
An= 3072
I think this is right :)
Answer:
3b+b and 2(2b)
Step-by-step explanation:
If they are two positive numbers, do it normally. If there is a negative and a positive, change it to addition and switch the SECOND integer sign. Only works with two integer…s in a subtraction question.
