All categories

3 years ago

A zip line takes passengers on a 200 m ride from high up in the trees to a ground level platform. If the

Mathematics

1 answer:

attashe74 [19]3 years ago

7 0

The zip line forms a right triangle with the tree, when elevated

The height of the tree is 35 meters

<h3>How to calculate the height of the tree</h3>

Represent the height of the tree with h.

So, the height h is calculated using the following sine function

$\sin(10) = \frac{h}{200}$

Make h the subject

h = 200 * sin(10)

Evaluate the product

h = 35 meters

Hence, the height of the tree is 35 meters

You might be interested in

A. What is the volume, in cubic feet, of the box in the diagram?

Allisa [31]

Volume is a three-dimensional scalar quantity. The number of boxes that can fit in the cargo hold of the truck is 54.

<h3>What is volume?</h3>

A volume is a scalar number that expresses the amount of three-dimensional space enclosed by a closed surface.

The volume of the box = Volume of the cube = a³ = (2.50)³ = 15.625 ft³

The volume of cargo hold = 7.50 × 7.50 × 15 = 843.75 ft³

Now, the number of boxes that can fit in the cargo hold of the truck will be,

Number of boxes = (Volume of truck container)/(Volume of box)

= 843.75/15.625

= 54

Hence, the number of boxes that can fit in the cargo hold of the truck is 54.

Learn more about Volume:

brainly.com/question/13338592

#SPJ1

5 0

2 years ago

Please help <br> Will give BRAINLIEST

Nady [450]

5.9 m
I solved it by adding some of the numbers that were in the picture & then added the m at the end because all of the other had it

7 0

3 years ago

1. Given the following relation, determine the inverse relation.

gayaneshka [121]

Answer:

1. a

2. $f^{-1} (x)=\frac{x}{2} +2$

Step-by-step explanation:

1. Since there is one value of y for every value of x in (−1,0),(−4,5),(3,2),(−3,5), this relation is a function.

2. To find the inverse, interchange the variables and solve for y.

$f^{-1} (x)=\frac{x}{2} +2$

5 0

3 years ago

Find the solution of the following equation whose argument is strictly between 270^\circ270 ∘ 270, degree and 360^\circ360 ∘ 360

Natasha2012 [34]

$\rightarrow z^4=-625\\\\\rightarrow z=(-625+0i)^{\frac{1}{4}}\\\\\rightarrow x+iy=(-625+0i)^{\frac{1}{4}}\\\\ x=r \cos A\\\\y=r \sin A\\\\r \cos A=-625\\\\ r \sin A=0\\\\x^2+y^2=625^{2}\\\\r^2=625^{2}\\\\|r|=625\\\\ \tan A=\frac{0}{-625}\\\\ \tan A=0\\\\ A=\pi\\\\\rightarrow z= [625(\cos (2k \pi+pi) +i \sin (2k\pi+ \pi)]^{\frac{1}{4}}\\\\k=0,1,2,3,4,....\\\\\rightarrow z=(625)^{\frac{1}{4}}[\cos \frac{(2k \pi+pi)}{4} +i \sin \frac{(2k\pi+ \pi)}{4}]$

$\rightarrow z_{0}=(625)^{\frac{1}{4}}[\cos \frac{pi}{4} +i \sin \frac{\pi)}{4}]\\\\\rightarrow z_{1}=(625)^{\frac{1}{4}}[\cos \frac{3\pi}{4} +i \sin \frac{3\pi}{4}]\\\\ \rightarrow z_{2}=(625)^{\frac{1}{4}}[\cos \frac{5\pi}{4} +i \sin \frac{5\pi}{4}]\\\\ \rightarrow z_{3}=(625)^{\frac{1}{4}}[\cos \frac{7\pi}{4} +i \sin \frac{7\pi}{4}]$