5, 5, 5, 5, 5, 1, 1, 1, 1, 1, 1. As you see those are eleven numbers/bills so your answer may be, The student has 5, 5$ bills and 6, 1$ bills. which makes up 31$.
So by having a circle with a diameter of 14 metres it is a sake of calculating the circumference of the patio. This is simply done by (where d = 2r, d is the diameter, and r the radius)