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MissTica
3 years ago
13

What is the simplest form of x2+5x-36/x2-16

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
6 0

Answer:

(x^4 + 5 x^3 - 16 x^2 - 36)/x^2

Step-by-step explanation:

Simplify the following:

x^2 + 5 x - 16 - 36/x^2

Put each term in x^2 + 5 x - 16 - 36/x^2 over the common denominator x^2: x^2 + 5 x - 16 - 36/x^2 = x^4/x^2 + (5 x^3)/x^2 - (16 x^2)/x^2 - 36/x^2:

x^4/x^2 + (5 x^3)/x^2 - (16 x^2)/x^2 - 36/x^2

x^4/x^2 + (5 x^3)/x^2 - (16 x^2)/x^2 - 36/x^2 = (x^4 + 5 x^3 - 16 x^2 - 36)/x^2:

Answer: (x^4 + 5 x^3 - 16 x^2 - 36)/x^2

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Find the cube root of 27d3 + 54a2b + 36ab2 + 8b3​
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Answer:

 (3a + 2b)3

Step-by-step explanation:

STEP 1  :

Equation at the end of step 1

 (((27•(a3))+((54•(a2))•b))+(36a•(b2)))+23b3

Step 2:

(((27•(a3))+((54•(a2))•b))+(22•32ab2))+23b3

Step 3:

(((27•(a3))+((2•33a2)•b))+(22•32ab2))+23b3

Step 4:

 ((33a3 +  (2•33a2b)) +  (22•32ab2)) +  23b3

Step 5:

 Factoring:  27a3+54a2b+36ab2+8b3

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3 years ago
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3 0
3 years ago
A company claims that the mean weight per apple they ship is 120 grams with a standard deviation of 12 grams. Data generated fro
Veronika [31]

Answer:

There is no sufficient evidence to reject the company's claim at the significance level of 0.05

Step-by-step explanation:

Let \mu be the true mean weight per apple the company ship.  We want to test the next hypothesis

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Because we have a large sample of size n = 49 apples randomly selected from a shipment, the test statistic is given by

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z_{0}=\frac{122.5-120}{12/\sqrt{49}}=1.4583. The rejection region for \alpha = 0.05 is given by RR = {z| z < -1.96 or z > 1.96} where the area below -1.96 and under the standard normal density is 0.025; and the area above 1.96 and under the standard normal density is 0.025 as well. Because the observed value 1.4583 does not fall inside the rejection region RR, we fail to reject the null hypothesis.

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3 years ago
Write the equation of the line in fully simplified slope-intercept form.​
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Calculate the mean, median, and mode of the following set of data. Round to the nearest tenth. 3, 15, 3, 3, 1, 11, 2, 8, 3, 7, 1
zubka84 [21]
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6 0
3 years ago
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