A cubical box 20.00 cm on a side is completely immersed in fluid. At the top of the box the pressure 105.0 kPa at the bottom the
1 answer:
Answer:
ρ = 900 kg/m³
Explanation:
Given that
a= 20 cm
Pressure at the top ,P₁ = 105 KPa
Pressure at the bottom,P₂= 106.8 KPa
Lets take the density of the fluid = ρ kg/m³
The pressure at the bottom given as
P₂ = P₁ + ρ g a
Now by putting the values
106.8 x 1000 = 105 x 1000+ ρ x 10 x 0.2 ( g= 10 m/s²)
1000(106.8 - 105) = 2 ρ
ρ = 900 kg/m³
Therefore the density of the fluid will be 900 kg/m³
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Answer:
Spring constant, k = 1.16 N/m
Explanation:
It is given that,
Mass of the air track, m = 0.2 kg
Time, t = 2.6 s
Let T is the time period of the spring. The expression for the time and spring constant is given by :
k = 1.16 N/m
So, the spring’s force constant is 1.16 N/m. Hence, this is the required solution.
Answer:
Explanation:
The acceleration of an object is given by
where
v is the final velocity
u is the initial velocity
t is the time it takes for the velocity to change from u to v
For the boat in the problem,
v = 10 m/s
u = 0
t = 2 s
Substituting, we find the acceleration