Dynamics Newton's 1st & 2nd Laws

Radiation from the sun hits Earth unequally and is absorbed by different materials in varying amounts. This is called

GenaCL600 [577]

Answer:

sorry I don't know what is the answer of this question

sorry for that sorry

4 0

2 years ago

Two infinite parallel surfaces carry uniform charge densities of 0.20 nC/m2 and -0.60 nC/m2. What is the magnitude of the electr

svlad2 [7]

Answer:

Electric field, E = 45.19 N/C

Explanation:

It is given that,

Surface charge density of first surface, $\sigma_1=0.2\ nC/m^2=0.2\times 10^{-9}\ C/m^2$

Surface charge density of second surface, $\sigma=-0.6\ nC/m^2=-0.6\times 10^{-9}\ C/m^2$

The electric field at a point between the two surfaces is given by :

$E=\dfrac{\sigma}{2\epsilon_o}$

$E=\dfrac{\sigma1-\sigma_2}{2\epsilon_o}$

$E=\dfrac{0.2\times 10^{-9}-(-0.6\times 10^{-9})}{2\times 8.85\times 10^{-12}}$

E = 45.19 N/C

So, the magnitude of the electric field at a point between the two surfaces is 45.19 N/C. Hence, this is the required solution.

6 0

3 years ago

Uses of Photodiode.State the 8 uses of phototide...................

Inessa05 [86]

Answer:

Photodiodes are used in consumer electronics devices such as compact disc players, smoke detectors, medical devices and the receivers for infrared remote control devices used to control equipment from televisions to air conditioners. For many applications either photodiodes or photoconductors may be used.

6 0

3 years ago

For a railgun, determine the current required to accelerate a 1000kg space vehicle to earths escape velocity on 10km of track wi

Troyanec [42]

Answer:

the current is 15.68 × $10^{5}$ A

Explanation:

mass = 1000 kg

magnetic fied = 2T

rail separation = 2m

escape velocity is 11.2km/s = 11.2 × $10^{3}$ m/s

distance = 10 km = $10^{4}$ m

to find out

determine the current

solution

we know force F = I×L×B

here I is current and L is rail separation and B is magnetic field

so F = I ×2×2 = 4 I

so

acceleration is a = $\frac{F}{mass}$

a = $\frac{4I}{1000}$ m/s²

so equation of motion

v²-u² = 2 a S

here u is initial velocity and S is distance and a is acceleration and v is final velocity

11.2 × $10^{3}$ - 0 = 2× $\frac{4I}{1000}$ × $10^{4}$

solve we get I

I = 15.68 × $10^{5}$ A

so the current is 15.68 × $10^{5}$ A

4 0

3 years ago

Altitude refers to ________________. Group of answer choices the angular distance from the celestial equator the angular height

liraira [26]

In Science, altitude refers to: D. the angular height away from the horizon.

<h3>What is altitude?</h3>

Altitude is also referred to as an elevation and it can be defined as the vertical distance (height) above a natural satellite or the surface of a planet such as land or sea level.

This ultimately implies that, an altitude is vertical height (elevation) of an object or physical body above a particular location or planetary reference plane such as land or sea level on Earth.

In conclusion, altitude is the angular height of an object or physical body away from the horizon.

Read more on altitude here: brainly.com/question/1159693

3 0

2 years ago