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Andreyy89
3 years ago
13

Dynamics Newton's 1st & 2nd Laws

Physics
1 answer:
pav-90 [236]3 years ago
8 0
Ummm what does this even mean I need a picture to help u
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A student was asked to push a large box down the hallway about 35 meters. the task took the student five minutes and a force of
zaharov [31]
Rate of work or Power done by the student can be computed with below formulas.
1. Formula for Work
Work = Force x distance
Force or F = Force applied to the object 
distance or d = displacement

2. Formula for Power
P = Work done / Time it was done or completed

Substituting the values we have,
Work or Work done = 150 N x 35 meters = 5250 J (unit of work).

Lastly computing for the rate we have,
Power or rate of work = 5250 J / 300 seconds (or 5 min) = 17.5 Joule/S or Watts

Answer is 17.5 watts

5 0
3 years ago
The heat capacity of an object depends in part on its ____.
nikdorinn [45]
If I remember it correctly, heat capacity is inversely proportional to mass so the answer is:
The heat capacity of an object depends in part on its a. mass
7 0
3 years ago
At the instant the traffic light turns green, an automobile that has been waiting at an intersection starts ahead with a constan
oksian1 [2.3K]

Answer:

(A) Distance taken by automobile to overtake truck is 175.23 m

(B) Final speed of the automobile is 29.6 m/s.

Explanation:

According to the problem, the automobile is at rest, so its initial speed is zero and the automobile is moving with constant acceleration.

The general equation of motion is:

d = ut + 0.5at²      .....(1)

Here d is distance, a is acceleration, t is time and u is initial speed.

The distance (d₁) travel by the automobile after green light in time t is given by the relation :

d₁ = u₁t + 0.5at²

We know that its initial velocity is zero i.e. u = 0 m/s.

d₁ = 0.5at²      ......(2)

The truck is moving with constant speed, so its acceleration is zero. Therefore, the distance covered by the truck using equation (1) is;

d₂ = u₂t         .......(3)

Since, the distance travelled by automobile and truck are same. Hence,

d₁ = d₂

0.5at² = u₂t

t = 2u₂/a

Substitute 14.8 m/s for u₂ and 2.50 m/s² for a in the above equation.

t = \frac{2\times14.8}{2.50}

t = 11.84 s

(A) Distance travelled by automobile, d = u₂t =14.8 x 11.84 = 175.23 m

(B) Final speed of the automobile is given by the relation:

v = u + at

v = 0 + 2.50 x 11.84

v = 29.6 m/s

4 0
3 years ago
What graph shows the relationship between kinetic energy and mass
Mrrafil [7]

It's definitely not one of the graphs you gave us to choose from.

5 0
3 years ago
3. If you increase the distance between
AURORKA [14]

Answer:

B

Explanation:

5 0
3 years ago
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