Information that is given:
a = -5.4m/s^2
v0 = 25 m/s
---------------------
S = ?
Calculate the S(distance car traveled) with the formula for velocity of decelerated motion:
v^2 = v0^2 - 2aS
The velocity at the end of the motion equals zero (0) because the car stops, so v=0.
0 = v0^2 - 2aS
v0^2 = 2aS
S = v0^2/2a
S = (25 m/s)^2/(2×5.4 m/s^2)
S = (25 m/s)^2/(10.8 m/s^2)
S = (625 m^2/s^2)/(10.8 m/s^2)
S = 57.87 m
The one fact that needs to be mentioned but isn't given anywhere on or around the graph is: The distance, on the vertical axis, is the distance FROM home. So any point on the graph where the distance is zero ... the point is in the x-axis ... is a point AT home.
Segment D ...
Walking AWAY from home; distance increases as time increases.
Segment B ...
Not walking; distance doesn't change as time increases.
Segment C ...
Walking away from home, but slower than before; distance increases as time increases, but not as fast. Slope is less than segment-D.
Segment A ...
Going home; distance is DEcreasing as time increases. Walking pretty fast ... the slope of the line is steep.
Explanation:
Given that,
Mass of the car, m₁ = 1250 kg
Initial speed of the car, u₁ = 7.39 m/s
Mass of the truck, m₂ = 5380 kg
It is stationary, u₂ = 0
Final speed of the truck, v₂ = 2.3 m/s
Let v₁ is the final velocity of the car. Using the conservation of momentum as :
So, the final velocity of the car is 2.5 m/s but in opposite direction. Hence, this is the required solution.
Answer: F = 1391 N
Explanation:
The information given to you are:
Mass M = 1300 kg
Acceleration a = 1.07 m/s^2
The magnitude of the force striking the building will be
F = ma
Where
F = force
Substitute mass M and acceleration a into the formula
F = 1300 × 1.07
F = 1391 N
Therefore, the wrecking ball strikes the building with a force of 1391 N
We'll look at two properties:
1. The variation in temperature
2. The material's heat transfer coefficient
By taking an example;
Use a circular rod made of a certain material (for example, steel) that is insulated all the way around.
One end of the rod is immersed in a huge reservoir of 100°C water, while the other is immersed in water at 40°C. The cold water is kept in an insulated cylinder on both sides. The temp of the chilly water is measured using a meter as a time - dependent.
Conclusion of experiment;
- Heat is transferred from a hot location to a cooler region.
- Whenever heat is applied to a body, its thermal power rises, and its temperature rises.
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