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3 years ago

4 x 10^6 is how many times large then 1 x 10^4

Mathematics

1 answer:

Molodets [167]3 years ago

4 0

Answer:

Step-by-step explanation:

$4\times10^6\text{ is how many times large than}\ 1 \times 10^4?\\\\\dfrac{4\times10^6}{1\times10^4}=\dfrac{4}{1}\times\dfrac{10^6}{10^4}=4\times10^{6-4}=4\times10^2=4\times100=400$

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What is even the question?

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The Children’s Hospital sponsors a 10K race to raise money. It receives $75 per race entry and $10,000 in donations, but it must

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THE ANSWER:

There would need to be at least 1,800 entries in order for them to meet their goal.

Step-by-step explanation:

To find this, we must write an equation that helps solve it. We know that for every entry (x), we gain 75 and lose 25. We can express this as the following.

75x - 25x

Then we can add the number of donations.

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Then we can set it as greater than or equal to the goal number.

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Now we solve this using the order of operations.

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There are big spenders among University of Alabama football season ticket holders. This data set Roll Tide!! shows the dollar am

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Using the z-distribution, as we have a proportion, the 95% confidence interval is (0.2316, 0.3112).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which:

$\pi$ is the sample proportion.

z is the critical value.

n is the sample size.

In this problem, we have a 95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so the critical value is z = 1.96.

We also consider that 130 out of the 479 season ticket holders spent $1000 or more at the previous two home football games, hence:

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Hence the bounds of the interval are found as follows:

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The 95% confidence interval is (0.2316, 0.3112).

More can be learned about the z-distribution at brainly.com/question/25890103

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2 years ago

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Answer:

Step-by-step explanation:

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