The equasion has only one solution.
<h3>
Answer: False</h3>
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Explanation:
I'm assuming you meant to type out
(y-2)^2 = y^2-6y+4
This equation is not true for all real numbers because the left hand side expands out like so
(y-2)^2
(y-2)(y-2)
x(y-2) .... let x = y-2
xy-2x
y(x)-2(x)
y(y-2)-2(y-2) ... replace x with y-2
y^2-2y-2y+4
y^2-4y+4
So if the claim was (y-2)^2 = y^2-4y+4, then the claim would be true. However, the right hand side we're given doesn't match up with y^2-4y+4
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Another approach is to pick some y value such as y = 2 to find that
(y-2)^2 = y^2-6y+4
(2-2)^2 = 2^2 - 6(2) + 4 .... plug in y = 2
0^2 = 2^2 - 6(2) + 4
0 = 4 - 6(2) + 4
0 = 4 - 12 + 4
0 = -4
We get a false statement. This is one counterexample showing the given equation is not true for all values of y.
For t=0
<span>Allan borrows--------------------------- > 1870 dollars
for t=6 years
</span>F1 = P*(1 +(r/m))^n
i=r/m
n=m*t---------- >1*6=6
we have
P1=1870
r=8%
m=1
t=6 years
F1 = 1870*(1 +(0.08/1))^6------------------ >2967.45 dollars
for t=2
Allan borrows--------------------------- > 1240 dollars
for t=6 years
F2 = P2*(1 +(r/m))^n
i=r/m
n=m*t---------- >1*4=4
we have
P2=1240
r=8%
m=1
t=4 years------------> (6-2)=4 years
F2 = 1240*(1 +(0.08/1))^4------------------ >1687 dollars
F1+F2=2967.45+1687=4654.45 dollars
the answer is 4654.45 dollars
Answer:
5.4 m
Step-by-step explanation:
The Pythagorean theorem tells you the relationship between the various lengths is ...
cd² = ac² +ad²
cd² = (2.4 m)² + (1.8 m)² = 9.00 m²
cd = √(9.00 m²) = 3.0 m
Since cd = cb and ab = ac+cb, we have ...
ab = 2.4 m + 3.0 m = 5.4 m
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You may recognize this as a 3-4-5 right triangle with a scale factor of 0.6. We are asked for the sum of the lengths of the "4" and "5" legs, which is ...
0.6·(4+5) = 5.4
