Complete the parametric equations for the given rectangular equation

Mathematics

1 answer:

Vera_Pavlovna [14]3 years ago

3 0

Answer:

a) y =t² -2t -3

b) x =3 sin t

Step-by-step explanation:

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A rectangle has a height of 6k3 and a width of 2k2 + 4k +5.

Trava [24]

Answer: $12k^5+24k^4+30k^3$

Step-by-step explanation:

Given : The height of the rectangle = $6k^3$

The width of the rectangle = $2k^2+4k+5$

Formula : Area = height x width

Therefore , the area of triangle in terms of polynomial will be :

$6k^3\times( 2k^2+4k+5)\\\\= 6k^3(2k^2)+6k^3(4k)+6k^3(5)\ \ [\text{Using Distributive property}]\\\\=12k^{3+2}+24k^{3+1}+30k^3\ \ [\text{Using exponents rule}:\ a^n\times a^m=a^{n+m}]\\\\=12k^5+24k^4+30k^3$

Hence, the area of the entire rectangle = $12k^5+24k^4+30k^3$

5 0

4 years ago

What type of parallelogram has

zlopas [31]

Answer:

Rhombus

Step-by-step explanation:

Parallelogram is a quadrilateral .
It has both 2pairs parallel and congruent.
Opposite sides are same

6 0

3 years ago

Read 2 more answers

I need help finishing a question. I used the explanation function on the program, but it didn't specify what to do to get the fi

leva [86]

I would compute sqrt(1 + 160pi^2) first to get approximately 39.75093337

Add this to 1 and we have 40.75093337

Then divide over 2pi to get a final approximate result of 6.48571248

So x = 6.48571248 is one approximate solution

In short, I computed $\frac{1+\sqrt{1+160\pi^2}}{2\pi}$ only focusing on the plus for now.

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If you were to compute $\frac{1-\sqrt{1+160\pi^2}}{2\pi}$ you should get roughly -6.167402596 as your other solution. Each solution can then be plugged into the original equation to check if you get 0 or not. You likely won't land exactly on 0 but you'll get close enough.