Error
<span>6 x = - 2 (5)
should be
</span><span>2 x = - 18 (5)
answer
</span><span>D.
Line 5</span>
Answer:
a) Discrete Variable
b) Continuous Variable
Step-by-step explanation:
We are given the following in the question:
Discrete and Continuous:
- Discrete data are the data whose value can be expressed in whole number. They cannot take all the values within an interval.
- Discrete variables are usually counted than measured.
- Continuous variable can be expressed in the form of decimals. They can take any value within an interval.
- Continuous variables are usually measured than counted.
(a) The number of free dash throw attempts before the first shot is made.
Since the number of shots made will always be expressed in whole numbers and the number of shots made will counted and not measured. Thus, number of free dash throw attempts before the first shot is made. is a discrete variable.
(b) The distance a baseball travels in the air after being hit.
The distance is a continuous variable as its value can be expressed in decimals. Also distance is always measured and not counted. Thus, distance a baseball travels in the air after being hit is a continuous variable.
Answer: 54
Step-by-step explanation:
3 times the square of -3 plus -5 times -3 plus 12
3 times 9 + 15 + 12
27+15+12=
54
Answer:
There are no like terms.
Step-by-step explanation:
Cone details:
Sphere details:
================
From the endpoints (EO, UO) of the circle to the center of the circle (O), the radius is will be always the same.
<u>Using Pythagoras Theorem</u>
(a)
TO² + TU² = OU²
(h-10)² + r² = 10² [insert values]
r² = 10² - (h-10)² [change sides]
r² = 100 - (h² -20h + 100) [expand]
r² = 100 - h² + 20h -100 [simplify]
r² = 20h - h² [shown]
r = √20h - h² ["r" in terms of "h"]
(b)
volume of cone = 1/3 * π * r² * h
===========================




To find maximum/minimum, we have to find first derivative.
(c)
<u>First derivative</u>

<u>apply chain rule</u>

<u>Equate the first derivative to zero, that is V'(x) = 0</u>




<u />
<u>maximum volume:</u> <u>when h = 40/3</u>


<u>minimum volume:</u> <u>when h = 0</u>

