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spin [16.1K]
2 years ago
9

Find the exact solution of x 3x^2+7=28 A.+√7 B.7 C.+7 D.-7

Mathematics
2 answers:
dolphi86 [110]2 years ago
5 0

Answer:

A. +\sqrt{7}

Step-by-step explanation:

3x^2+7=28
3(+\sqrt{7} ^{2} )+7=28

3(7)+7=28

21+7=28
28=28

Hope it helps

yulyashka [42]2 years ago
3 0

Answer:

x = ± \sqrt{7}

Step-by-step explanation:

3x² + 7 = 28 ( subtract 7 from both sides )

3x² = 21 ( divide both sides by 3 )

x² = 7 ( take square root of both sides )

x = ± \sqrt{7}

that is x = - \sqrt{7} , x = \sqrt{7}

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Solve 3^x − 2 = 3^7<br><br> A. 2<br> B. 5<br> C. 7<br> D. 9
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Answer:

C) 7

Step-by-step explanation:

3^x−2=2187

Step 1: Add 2 to both sides.

3^x−2+2=2187+2

3^x=2189

Step 2: Solve Exponent.

3^x=2189

log(3x)=log(2189)        <<Take log of both sides

x*(log(3))=log(2189)

x= log(2189)/log(3)

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F(x) = 2x + 3g(x) = 2x² + 6x + 13Find: (gºf)(x)
Butoxors [25]

Answer:

The function (gof)(x) is;

(g\circ f)(x)=8x^2+36x+49

Explanation:

Given the functions;

\begin{gathered} f(x)=2x+3 \\ g(x)=2x^2+6x+13 \end{gathered}

Solving for the function;

(g\circ f)(x)=g(f(x))

so, we have;

\begin{gathered} g(f(x))=2(f(x))^2+6(f(x))+13 \\ g(f(x))=2(2x+3)^2+6(2x+3)+13 \\ g(f(x))=2(4x^2+12x+9)^{}+6(2x)+6(3)+13 \\ g(f(x))=8x^2+24x+18^{}+12x+18+13 \\ g(f(x))=8x^2+24x^{}+12x+18+18+13 \\ g(f(x))=8x^2+36x+49 \end{gathered}

Therefore, the function (gof)(x) is;

(g\circ f)(x)=8x^2+36x+49

5 0
1 year ago
Analyze the diagram below and complete the instructions that follow. / Find the value of x. A. 4 B. 5 C. 6 D. 9
WARRIOR [948]

Answer:

C

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3 years ago
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