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Nastasia [14]
3 years ago
13

How many valence electrons does this atom have?

Chemistry
1 answer:
frosja888 [35]3 years ago
8 0

Answer:

4

Explanation:

The given atomic structure appears to have 2 shells/orbits containing electrons – 2 in the inner orbit and 4 in the outer orbit.

Since valence electrons are the electrons present in the outermost orbit/shell of an atom, their number in the given atom becomes 4. <em>(If </em><em>the</em> <em>2nd orbit is the outermost orbit, the number of electrons it contains becomes the number of valence electrons).</em>

Why is the number of valence electrons important?

Atoms are neutral, that contain an equal amount of positive and negative charges. All atoms are not stable. Their stability depends upon the number of electrons in specific orbits,( <em>for eg</em><em> </em><em> </em><em>2</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>innermost</em><em> </em><em>orbit</em><em>,</em><em> </em><em>then</em><em> </em><em>8</em><em>,</em><em> </em><em>1</em><em>8</em><em> </em><em>and</em><em> </em><em>so</em><em> </em><em>on</em><em>.</em><em>)</em>

Valence electrons are loosely attracted by the nucleus and hence can easily be removed from an atom. The number of valence electrons an atom needs to donate/share/accept becomes its valency.

For elements and compounds to exist, the atoms they contain demand stability – which can only be attained by the loss/gain of these <u>valence electrons.</u>

<u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u>

For more information, visit:

brainly.com/question/12717954

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BartSMP [9]

Answer:

The empirical formula of ribose (a sugar) is CH2O. In a separate experiment, using a mass spectrometer, the molar mass of ribose was determined to be 150 g/mol.Explanation:

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Hello!
blondinia [14]

Answer:

[CO]=[Cl_2]=0.01436M

[COCl_2]=0.00064M

Explanation:

Hello there!

In this case, according to the given chemical reaction at equilibrium, we can set up the equilibrium expression as follows:

K=\frac{[CO][Cl_2]}{[COCl_2]}

Which can be written in terms of x, according to the ICE table:

0.32=\frac{x^2}{0.015M-x}

Thus, we solve for x to obtain that it has a value of 0.01436 M and therefore, the concentrations at equilibrium turn out to be:

[CO]=[Cl_2]=0.01436M

[COCl_2]=0.015M-0.01436M=0.00064M

Regards!

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3 years ago
How does a negative ion differ from a positive?
Ilya [14]
A negative ion or anion is an electrically charged atom or group of atoms that are formed by gaining one or more electrons. Whereas a positive ion or cation is an electrically charged atom or group of atoms that are formed by losing one or more electrons. 
The losing and gaining all occurs on the outermost shell. 
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3 years ago
Chemicals used in a laboratory investigation must be safely discarded. Which method is the safest way to dispose of chemicals at
Tema [17]

Answer:

Disposing of the discarded chemicals can be done by certain sfae methods mention as follows:

Explanation:

Most of the chemical wastes are dispose through the EHS waste program. Organic chemicals and solvents that can not be drain should be closed in a tight fitted container that has label on it as Hazardous waste, including strong acid and corrosive liquids.

Recycling of these chemicals and incineration is also use for the industrial chemical waste under professional guidance. Incineration is the process of burning chemicals in to ash through high thermal burning.

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3 years ago
Fill in the left side of this equilibrium constant equation for the reaction of benzoic acid (HC_6H_5CO_2) with water.
il63 [147K]

Answer:

[C₆H₅COO⁻][H₃O⁺]/[C₆H₅COOH] = Ka

Explanation:

The reaction of dissociation of the benzoic acid in water is given by the following equation:

C₆H₅-COOH + H₂O  ⇄  C₆H₅-COO⁻  +  H₃O⁺    (1)

The dissociation constant of an acid is the measure of the strength of an acid:

HA ⇄ A⁻ + H⁺        (2)

K_{a} = \frac{[A^{-}][H^{+}]}{[HA]}      (3)

<em>Where the dissociation constant of the acid (Ka) is equal to the ratio of the concentration of the dissociated forms of the acid, [A⁻][H⁺], and the concentration of the acid, [HA].     </em>

So, starting from the equations (2) and (3), the constant equation for the dissociation reaction of benzoic acid in water, of the equation (1), is:

K_{a} = \frac{[C_{6}H_{5}COO^{-}][H_{3}O^{+}]}{[C_{6}H_{5}COOH]}

I hope it helps you!          

6 0
3 years ago
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