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3 years ago

Write two reactions showing nascent Hydrogen is more reactive than molecular Hydrogen.

Chemistry

1 answer:

ratelena [41]3 years ago

4 0

Answer:

1.) Nascent Hydrogen has more energy than Molecular Hydrogen.

2.) Nascent Hydrogen is are more on the side of atomic and since atoms are more active than molecules, Nascent Hydrogen becomes more reactive.

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Why are the outer-most electrons the only ones included in the electron dot diagram?

kupik [55]

Answer:

Atoms with 5 or more valence electrons gain electrons forming a negative ion, or anion. why are outermost electrons only ones included in orbital filling diagram? they are the only ones involved in chemical reactions and bonding. ... 2s orbital is farther from the nucleus meaning it has more energy.

Explanation:

8 0

4 years ago

The basic premise of the collision theory is that particles must first _______________ if a reaction is to occur. Additionally,

Irina-Kira [14]

Answer: Collide, Collision, Collide, Proper Orientation and Energy

Explanation:

The basic premise of the collision theory is that particles must first collide if a reaction is to occur. Additionally, that collision must be effective. To be effective, the particles must collide with the proper orientation and the proper amount of energy.

6 0

3 years ago

The molecular weight of an organic compound was determined by measuring the freezing point depression of a benzene solution. A 0

Rudiy27

Answer: The molar mass of the sample is 120.6 g/mol

Explanation:

To calculate the depression in freezing point, we use the equation:

$\Delta T_f=iK_fm$

Or,

$\Delta T_f=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}$

where,

$\Delta T_f$ = depression in freezing point = 0.42°C

i = Vant hoff factor = 1 (For non-electrolytes)

$K_f$ = molal freezing point elevation constant = 5.065°C/m

$m_{solute}$ = Given mass of solute (sample) = 0.500 g

$M_{solute}$ = Molar mass of solute (sample) = ? g/mol

$W_{solvent}$ = Mass of solvent (benzene) = 50.0 g

Putting values in above equation, we get:

$0.42^oC=1\times 5.065^oC/m\times \frac{0.500\times 1000}{M_{solute}\times 50.0}\\\\M_{solute}=\frac{1\times 5.065\times 0.500\times 1000}{50.0\times 0.42}=120.6g/mol$

Hence, the molar mass of the sample is 120.6 g/mol

5 0

4 years ago

If a particular ore contains 55.1 % calcium phosphate, what minimum mass of the ore must be processed to

Diano4ka-milaya [45]

Answer:

6049.69 g or 6.04969 Kg of ore must be processed to get 1 Kg of phosphorous.

Explanation:

Given

An ore has 51% Calcium phosphate

To find

The minimum mass of ore to be processed to get 1.00 Kg of phosphorous

First find the mass of phosphorous in 1 mole = molar mass of Calcium phosphate, Ca₃(PO₄)₃.

Molar mass of Ca₃(PO₄)₃ is 310 g

Molar mass of P is 31 g

1 mole of Ca₃(PO₄)₃ has 3 atoms of phosphorous

i.e 310 g of Ca₃(PO₄)₃ has 3× 31g of P

= 93 g P

93 g P wil be present in 310 g of Ca₃(PO₄)₃

1 Kg or 1000 g of P will be in (1000÷93) ×310

=3333.33 g of Ca₃(PO₄)₃

but the ore has only 55.1% Ca₃(PO₄)₃

i.e

100 g of Ca₃(PO₄)₃ will have 55.1g Ca₃(PO₄)₃

we need 3333.33g of Ca₃(PO₄)₃

100 g of ore will have 55.1g Ca₃(PO₄)₃

3333.33g of Ca₃(PO₄)₃ will be present in

(3333.33÷ 55.1) ×100

= 6049.60 g of the ore

So 6049.69 g or 6.04969 Kg of ore must be processed to get 1 Kg of phosphorous.

3 0

4 years ago

Based on relative bond strengths, classify these reactions as endothermic (energy absorbed) or exothermic (energy released).

mel-nik [20]

Answer:

1. Exothermic 2. Exothermic 3. Endothermic 4. Endothermic 5. Exothermic.

Explanation:

1. An A-A and a C-C bond results in 2 A-C bonds which are lower than the A-A and C-C bonds so this reaction is exothermic.

2. A B-B bond and a C-C bond results in 2 B-C bonds which are lower than the first 2 bonds so this reaction is also exothermic.

3. There is no bond for single A, a single B-C bond results in a A-B bond and a C molecule. A-B bond is stronger than the B-C bond so the reaction absorbed energy along the way. This shows that it is endothermic.

4. An A-A bond and a B-B bond results in 2 A-B bonds which are stronger than the first two bonds so this reaction is also endothermic.

5. An A-B bond and a C molecule result in an A-C bond and a B molecule. A-C bond is weaker than the A-B bond so there is energy released. This reaction is exothermic.

I hope this answer helps.

8 0

3 years ago