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Cerrena [4.2K]
3 years ago
12

Given: <6 = <7

Mathematics
1 answer:
mart [117]3 years ago
8 0

∠6 is vertical to ∠5 and ∠7 is vertical to ∠8. If ∠6=∠7 then ∠5=∠8

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mark invests 8000 in an account that pays 12% interest and 2000 in one that pays 8%. if he leaves the money in the accounts for
frez [133]

mark must leave it for 5.5 months or 5 and half moths to gain 5600 in interest​ .

<u>Step-by-step explanation:</u>

Here we have , mark invests 8000 in an account that pays 12% interest and 2000 in one that pays 8%. if he leaves the money in the accounts for the same length of time, We need to find how long must he leave it to gain 5600 in interest​ . Let's find out:

Let mark invests 8000 in an account that pays 12% interest and 2000 in one that pays 8% for time x months , So total interest gain is 5600 i.e.

⇒ \frac{8000(12)}{100}(x) +\frac{2000(8)}{100}(x) =5600

⇒ \frac{8000(12)+2000(8)}{100}(x) =5600

⇒ (80(12)+20(8))(x) =5600

⇒ (960+160)(x) =5600

⇒ (1020)(x) =5600

⇒ x =\frac{5600}{1020}

⇒ x =5.5

Therefore , mark must leave it for 5.5 months or 5 and half moths to gain 5600 in interest​ .

6 0
3 years ago
Please help me with this problem​
victus00 [196]

Answer:

c

Step-by-step explanation:

y+3=\sqrt{\frac{x}{16}+2 } \\y=\sqrt{\frac{x+32}{16} } -3\\y=\frac{1}{4} \sqrt{x-(-32)} +(-3)\\so ~C

5 0
3 years ago
Which of the following is true of the data represented by the box plot
zmey [24]

Answer:

The data is skewed to the bottom and contains an outlier.  

Step-by-step explanation:

1. Test for outlier

An outlier is a point that is more than 1.5IQR below Q1 or above Q3.  

IQR = Q3 - Q1 = 74 - 51 = 23

1.5 IQR  = 1.5 × 23 = 34.5

51 - 15 = 36 > 1.5IQR

The point at 15 is an outlier.

2. Test for normal distribution

The median is not in the middle of the box.  

Rather, it cuts the box into two unequal parts, so the data does not have a normal distribution.

3. Test for skewness

The longer part is to the left of the median, so the data is skewed left.

 

4 0
3 years ago
The price of one share of a stock fell 4 dollars each day for 8 days. How much value did one share of the stock lose after 8 day
ivolga24 [154]

Answer:

After 8 days, the stock lost 32 dollars.

Step-by-step explanation:

If 4 dollars fell every day for 8 days, it would be 32 dollars because 4*8 is 32.

5 0
3 years ago
What is the equation of a line that is perpendicular to the line y= -1/4x - 1 and passes through the point (3,7) ?
kenny6666 [7]

Answer:

hahah idont know

Step-by-step explanation:

8293894=2893849222

7 0
3 years ago
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