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2 years ago

12

Given: <6 = <7

1 answer:

mart [117]2 years ago

8 0

∠6 is vertical to ∠5 and ∠7 is vertical to ∠8. If ∠6=∠7 then ∠5=∠8

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What is the area of a circle with a radius of 42 in use 3.14 for pi

Vanyuwa [196]

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2 years ago

Read 2 more answers

7z2 5z4 d3 d8<br> I don't know how you are supposed to do it?

Serga [27]

Answer:

$35 {z}^{6} {d}^{11}$

Step-by-step explanation:

Assuming you are supposed to simplify:

$7 {z}^{2} \times 5 {z}^{4} \times {d}^{3} \times {d}^{8}$

Then we need to apply the product rule of indices.

${a}^{m} \times {a}^{n} = {a}^{m + n}$

So we multiply to get:

$35 {z}^{2 + 4} \times {d}^{3 + 8}$

We now simplify the exponents to get:

$35 {z}^{6} \times {d}^{11}$

Therefore the required product is

$35 {z}^{6} {d}^{11}$

3 0

3 years ago

Triangle ABC is located at A(-4,5), B (-4, -1), and C(-1,1). A translation of the triangle is located at A’(-1, 7), B’(-1, 1), a

astraxan [27]

Triangle ABC is translated 3 units right and 2 units up
by looking at point A (-4,5) which is translated to A'(-1,7)
we can tell by looking at the points that -4 is shifted by 3 units to the right ti reach -1 and 5 is shifted upwards by 2 units to reach 7

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3 years ago

Using the x,y format where does the graph of 3x+3 and -5×+7 intersect

IRINA_888 [86]

Not sure if I'm right but I believe they intersect at (1,4).

8 0

3 years ago

Read 2 more answers

Find two complex numbers that have a sum of i10 a different of -4and a product of -29

lianna [129]

<h2>-2+5i and 2+5i</h2>

Step-by-step explanation:

Let the complex numbers be $a+ib\textrm{ and }c+id$ .

Given, sum is $10i$ , difference is $-4$ and product is $-29$ .

$(a+c)+i(b+d)=10i$ ⇒ $a+c=0,b+d=10$

$(a-c)+i(b-d)=-4$ ⇒ $a-c=-4,b-d=0$

$a=-2,c=2,b=5,d=5$

$(a+ib)(c+id)=(-2+5i)(2+5i)=-4-25=-29$

Hence, all three equations are consistent yielding the complex numbers $-2+5i\textrm{ and }2+5i$ .

8 0

3 years ago