Harry has five a1 bills, three $ 10 bills, and

Mathematics

1 answer:

Flura [38]2 years ago

4 0

Answer:

$\frac{1}{45}$ chance to grab both $20 bills

Step-by-step explanation:

There are ten bills in total.

The probability that the first dollar she picks is a twenty-dollar bill is 2/10 because she can pick either of the two twenty-dollar bills out of the ten in her wallet. Next, we need to pick the second bill. There are nine bills left, and only one is a twenty-dollar bill. The probability of choosing a second dollar bill is 1/9.

(2/10)*(1/9)=2/90=1/45

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