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aliina [53]
3 years ago
6

A rectangular note card is 4 inches tall and 7 inches wide. What is its area? square inches​

Mathematics
1 answer:
Softa [21]3 years ago
7 0

Answer:

28

Step-by-step explanation:

just multiply width times length 4*7=28

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Sara was thinking of a number. Sara subtracts 9 from it and gets an answer of 0.4. What was the original number?
Dmitrij [34]

Answer:

-8.6

Step-by-step explanation:

......................

6 0
3 years ago
Can you help me out it would be much appreciate thank you
brilliants [131]

Answer:

The answer to the question is 50.28 feet²

Step-by-step explanation:

Here, is why the answer to the problem is 13.72!

The area of the shaded region is:-

Area of total region - Area of the circular region

Area of total region is 8² so it is 64 feet²

Area of Circular region formula is πr²

Substitute the values, for the formula and it is π4² = 22/7 × 16

                                                                         → 352/7

                                                                        ⇒ 13.72 Feet²

Therefore, the area of the shaded region is 13.72 Feet²

(Now, we subtract the two values)

64 - 13.72

⇒ 50.28 Feet²

I hope this answer helps!

7 0
3 years ago
What is the solution set of x^2-10=30x
ch4aika [34]

x= 1/5

12-10=30x  subtract them

2=30x  switch the sides

30x=2  and you get x=1/5

8 0
4 years ago
Find the area of the triangle.<br> A. 73.6ft^2<br> B. 65.8 ft^2<br> C. 69.1 ft^2<br> D. 70.8 ft^2
spayn [35]
Please look at the picture for a step by step explanation - Answer choice is A

3 0
3 years ago
Please answer quickly! Several questions from Algebra 2, on a unit about Sequences and Series, most of these have to do with Ari
AnnyKZ [126]

The sum of the geometric series is 2199; option E.

  • The 36th term of the arithmetic series is -60.5 option C
  • The sum of the arithmetic series is 2547; option E
  • The missing geometric sequence are; 1.614375, 3.30946875, 6.7844109375. option E

<h3>Arithmetic and Geometric series</h3>

  • a1 = 1458
  • r = 1/3
  • a6 = 6

S6 = a(rⁿ - 1) / r -1

= 1468(1/3^6 - 1) / (1/3 - 1)

= 1468(0.00137174211248 - 1) / -2/3

= 1468(-0.9986282578875) / -0.66666666666666

= -1,465.98628257885 / -0.66666666666666

= 2198.97942386829

Approximately,

S6 = 2199

Arithmetic series

  • a36
  • a1 = 27
  • d = -5/2

Sn = n/2{2a + (n -1)d}

= 36/2 {2×27 + (36-1)-5/2}

= 18{54 + (35)-5/2}

= 18(54 + 175/2)

= 18(54 + 87.5)

= 18(141.5)

s36 = 2547

a36 = a + (n - 1) d

= 27 + (36 - 1)-5/2

= 27 + (35)-5/2

=27 + -175/2

= 27 - 87.5

= -60.5

S20 = n/2{2a + (n -1)d}

= 20/2{2×27 + (20-1)-5}

= 10(54 + (19)-5)

= 10{54 + (-95)}

= 10(54-95)

= 10(-41)

s20 = -410

Missing terms of the geometric sequence:

nth term = ar^n-1

448/135 = 63/80×r^(6-1)

448/135 = 63/80×r^5

r^5 = 448/135 ÷ 63/80

= 448/135 × 80/63

= 35,840/8,505

r = 5√35,840/5√8505

= 946.57/461.11

r = 2.05

Second term = a×r

= 63/80×2.05

= 1.614375

Third term = ar²

= 63/80×2.05²

= 63/80×4.2025

= 3.30946875

Fourth term = 63/80 × 2.05³

= 63/80×8.615125

= 6.7844109375

Therefore, none of these are correct

Learn more about sum of geometric series:

brainly.com/question/24643676

#SPJ1

4 0
2 years ago
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