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aliina [53]
3 years ago
6

A rectangular note card is 4 inches tall and 7 inches wide. What is its area? square inches​

Mathematics
1 answer:
Softa [21]3 years ago
7 0

Answer:

28

Step-by-step explanation:

just multiply width times length 4*7=28

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I need help I’m bad at math
Alina [70]
If you'd graph this function, you'd see that it's positive on [-1.5,0], and that it's possible to inscribe 3 rectangles on the intervals [-1.5,-1), (-1,-0.5), (-0.5, 1].

The width of each rect. is 1/2.

The heights of the 3 inscribed rect. are {-2.25+6, -1+6, -.25+6} = {3.75,5,5.75}.

The areas of these 3 inscribed rect. are (1/2)*{3.75,5,5.75}, which come out to:

{1.875, 2.5, 2.875}

Add these three areas together; you sum will represent the approx. area under the given curve on the given interval:  1.875+2.5+2.875 = ?
5 0
3 years ago
Three different units of measurement that could be used to identify area
vitfil [10]

Answer:

i hope it helps u........

8 0
3 years ago
Please help this is going to be due soon it’s a test
grandymaker [24]

Answer:

You are not allowed to use brainly for tests.. it is agianst their rules..

Step-by-step explanation:

8 0
3 years ago
What is the area of ABC?
Salsk061 [2.6K]

Answer:

Area of triangle ABC = 10

Option C is correct.

Step-by-step explanation:

We need to find area of triangle ABC

We are given A(2,1) B(4,7) and C(6,3)

The formula used to find Area \ of \ triangle=\frac{1}{2}base\times height ABC is:

In the given triangle base= AC and height = BC

First we need to find the distance between A and C and B and C

The formula used to find distance between AC Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

We have x_1=2, y_1=1, x_2=6, y_2=3

Putting values and finding distance

Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\Distance=\sqrt{(6-2)^2+(3-1)^2}\\Distance=\sqrt{(4)^2+(2)^2}\\Distance=\sqrt{16+4}\\Distance=\sqrt{20}

find distance between BC Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

We have x_1=4, y_1=7, x_2=6, y_2=3

Putting values and finding distance

Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\Distance=\sqrt{(6-4)^2+(3-7)^2}\\Distance=\sqrt{(2)^2+(4)^2}\\Distance=\sqrt{4+16}\\Distance=\sqrt{20}

So, We have height = \sqrt{20} and base = \sqrt{20}

Finding area of triangle

Area \ of \ triangle=\frac{1}{2}base\times height\\Area \ of \ triangle=\frac{1}{2}\sqrt{20} \times \sqrt{20} \\Area \ of \ triangle=\frac{1}{2}\times 20\\Area \ of \ triangle=10

So, Area of triangle ABC = 10

Option C is correct.

7 0
3 years ago
I will give brainliest to the right answer:)
Akimi4 [234]

Answer:

178.1

Step-by-step explanation:

In the first blank, write in 7 for x, and in the second blank, write in 8 for y.  Then perform the indicated multiplication and addition.

12.3(7) + 11.5(8), or

86.1    +  92   =   178.1

5 0
3 years ago
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