The two points where they end and the point where they start form a right triangle, one leg is 12, the other leg is 15, you need to find the hypotenuse.
use the Pythagorean theorem: 12²+15²=c²
c≈19
they are about 19 feet apart.
Answer:
Step-by-step explanation:
Calling it blocks is a little weird. but a good way to do it is to move left or right until you are over or below where you want to go then move up or down accordingly. Each move, left, right up or down will count as one block.
So from the fire station you go 1 to the right and then 6 down, for a total of 7. then from the library it's 3 right then 4 up, which is 7 again. 7 to the first stop then 7 to the second makes 14 total.
If there's something you don't get let me know.
Answer:
TRUE
Step-by-step explanation:
A quadratic equation can be found that will go through any three distinct points that ...
- satisfy the requirements for a function
- are not on the same line
_____
The key word here is "may." You will not be able to find a quadratic intersecting the three points if they do not meet both requirements above.
Answer:
Rhombus
Step-by-step explanation:
it's like a diamond but it's a little bit thicker
The equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2
<h3>How to determine the functions?</h3>
A quadratic function is represented as:
y = a(x - h)^2 + k
<u>Question #6</u>
The vertex of the graph is
(h, k) = (-1, 2)
So, we have:
y = a(x + 1)^2 + 2
The graph pass through the f(0) = -2
So, we have:
-2 = a(0 + 1)^2 + 2
Evaluate the like terms
a = -4
Substitute a = -4 in y = a(x + 1)^2 + 2
y = -4(x + 1)^2 + 2
<u>Question #7</u>
The vertex of the graph is
(h, k) = (2, 1)
So, we have:
y = a(x - 2)^2 + 1
The graph pass through (1, 3)
So, we have:
3 = a(1 - 2)^2 + 1
Evaluate the like terms
a = 2
Substitute a = 2 in y = a(x - 2)^2 + 1
y = 2(x - 2)^2 + 1
<u>Question #8</u>
The vertex of the graph is
(h, k) = (1, -2)
So, we have:
y = a(x - 1)^2 - 2
The graph pass through (0, -3)
So, we have:
-3 = a(0 - 1)^2 - 2
Evaluate the like terms
a = -1
Substitute a = -1 in y = a(x - 1)^2 - 2
y = -(x - 1)^2 - 2
Hence, the equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2
Read more about parabola at:
brainly.com/question/1480401
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