Answer:
what you marked blue is right
Step-by-step explanation:
I think
Answer:
B
Step-by-step explanation:
Using the determinant to determine the type of zeros
Given
f(x) = ax² + bx + c ( a ≠ 0 ) ← in standard form, then the discriminant is
Δ = b² - 4ac
• If b² - 4ac > 0 then 2 real and distinct zeros
• If b² - 4ac = 0 then 2 real and equal zeros
• If b² - 4ac < 0 then 2 complex zeros
Given
f(x) = (x - 1)² + 1 ← expand factor and simplify
= x² - 2x + 1 + 1
= x² - 2x + 2 ← in standard form
with a = 1, b = - 2, c = 2, then
b² - 4ac = (- 2)² - (4 × 1 × 2) = 4 - 8 = - 4
Since b² - 4ac < 0 then the zeros are complex
Thus P(x) has no real zeros
One is going 52 and the other 64
2 (x)+2 (x+12)=232 and solve
I think they’re perpendicular lines
Answer:
5 is congruent, 6 is not congruent
Step-by-step explanation:
In 5, both shapes have the same side lengths. This means their areas are the same, making them congruent.
In 6, the shapes do not have the same side lengths. This means their areas are not the same, making them not congruent.
