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Vikki [24]
2 years ago
5

What are distillation and evaporation most often used to separate in a science lab and why?

Physics
2 answers:
Alex777 [14]2 years ago
3 0
C because I think that’s the answer
sattari [20]2 years ago
3 0
B is the answer to your question it makes most sense to me
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Can someone please help me I don’t understand this please show work plus I got it wrong it’s not C
matrenka [14]
B,
The 25 N and 5 N force are acting in the same direction so we can add them together, but the 10 N force acts in the opposite direction so you subtract it.
25 N + 5 N - 10 N = 20 N
8 0
3 years ago
An object moves at constant speed along a circular path in a horizontal plane, with the center at the origin. When the object is
guapka [62]

Answer:

a)Counterclockwise

b)ω=2 rad/s

Explanation:

Given that

Object at = --2 m

r= - 2 m

Velocity pf object V = - 4 m/s

We know that

\vec{V}=\vec{\omega }\times \vec{r}

r= - 2 i m

V= - 4 j m/s

- 4 j= ω x (- 2 i)

ω  should be in counter clockwise (k) to satisfy the above equation.

It means that the direction of object will in counter clockwise.

4 = ω x 2

ω=2 rad/s

So object velocity at 2 m will be 2 rad/s.

6 0
3 years ago
The continuous flow of electrons is called ___________.
Brilliant_brown [7]
D. electrical current
4 0
3 years ago
A test tube of length L and cross-sectional area A is submerged in water with the open end down so that the edge of the tube is
Margaret [11]

Answer:

if we measure the change in height of the gas within the had and obtain a straight line in relation to the depth we can conclude that the air complies with Boye's law.

Explanation:

The air in the tube can be considered an ideal gas,

           P V = nR T

In that case we have the tube in the air where the pressure is P1 = P_atm, then we introduce the tube to the water to a depth H

For pressure the open end of the tube is

         P₂ = P_atm + ρ g H

Let's write the gas equation for the colon

            P₁ V₁ = P₂ V₂

            P_atm V₁ = (P_atm + ρ g H) V₂

             V₂ = V₁    P_atm / (P_atm + ρ g h)

If the air obeys Boyle's law e; volume within the had must decrease due to the increase in pressure, if we measure the change in height of the gas within the had and obtain a straight line in relation to the depth we can conclude that the air complies with Boye's law.

The main assumption is that the temperature during the experiment does not change

6 0
3 years ago
Select the appropriate shape for the given volume form
vredina [299]
Fist one is a cylinder
the second, i believe is a sphere
the third is a rectangular prism
and the last is the same as the first, a cylinder
3 0
2 years ago
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