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Alex Ar [27]
3 years ago
14

A health care provider suspects a client has developed posttraumatic stress disorder (PTSD). Select the necessary criterion to v

alidate the diagnosis.
Physics
1 answer:
julia-pushkina [17]3 years ago
8 0

Answer:

The necessary criterion to validate the PTSD (posttraumatic stress disorder) is criterion A, (one required): the person was exposed to: death, threatened death, actual or threatened serious injury, or actual or threatened sexual violence,one symptom (or more): inability to remember an important aspect of the event, from criterion B, one symptom (or more): wars survivors, persistent and exaggerated negative beliefs about oneself, others, or the world, and persistent negative emotional state.to criterion C: old age abused; persistent distorted cognitions about the cause or consequences of the event.

Explanation:

DSM-5 PTSD diagnosis measures, assesses, or evaluates dissociative subtypes, which causes disconnection from the surrounding world or from oneself.

The DSM-5 manual, for the PTSD diagnosis, includes the DSM-IV/ICD-9 309.81 to the ICD-10 F43.10.

An experienced mental health provider, such as a psychiatrist or psychologist, is generally in charge of the diagnosis.

To be diagnosed with PTSD, an adult must have at least one avoidance symptom re-experiencing symptom for at least 1 month.

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Damm [24]

I believe the answer is resonance

6 0
3 years ago
The terminal velocity of a person falling in air depends upon the weight and the area of the person facing the fluid. Find the t
Serga [27]

Answer:

115 m/s, 414 km/hr

Explanation:

There are two forces acting on a skydiver: gravity and air resistance (drag).  At terminal velocity, the two forces are equal and opposite.

∑F = ma

D − mg = 0

D = mg

Drag force is defined as:

D = ½ ρ v² C A

where ρ is the fluid density,

v is the velocity,

C is the drag coefficient,

and A is the cross sectional surface area.

Substituting and solving for v:

½ ρ v² C A = mg

v² = 2mg / (ρCA)

v = √(2mg / (ρCA))

We're given values for m and A, and we know the value of g.  We need to look up ρ and C.

Density of air depends on pressure and temperature (which vary with elevation), but we can estimate ρ ≈ 1.21 kg/m³.

For a skydiver falling headfirst, C ≈ 0.7.

Substituting all values:

v = √(2 × 80.0 kg × 9.8 m/s² / (1.21 kg/m³ × 0.7 × 0.140 m²))

v = 115 m/s

v = 115 m/s × (1 km / 1000 m) × (3600 s / hr)

v = 414 km/hr

4 0
3 years ago
To construct a non-mechanical water meter, a 0.500-T magnetic field is placed across the supply water pipe to a home and the Hal
Alex73 [517]

Answer:

a.  4 m/s b. 0.2 V

Explanation:

a. Find the flow rate through a 3.00-cm-diameter pipe if the Hall voltage is 60.0 mV.

The hall voltage V = vBd where v = flow-rate, B = magnetic field strength = 0.500 T and d = diameter of pipe = 3.00 cm = 0.03 m

Since V = vBd

v = V/Bd    given that V = 60.0 mV = 0.060 V, substituting the values of the other variables, we have

v = 0.060 V/(0.500 T × 0.03 m)

v = 0.060 V/(0.015 Tm)

v = 4 m/s

b. What would the Hall voltage be for the same flow rate through a 10.0-cm-diameter pipe with the same field applied?

Since the hall voltage, V = vBd and v = flow-rate = 4 m/s, B = magnetic field strength = 0.500 T and d' = diameter of pipe = 10.0 cm = 0.10 m

Substituting the variables into the equation, we have

V = vBd

V = 4 m/s × 0.500 T × 0.10 m

V = 0.2 V

6 0
3 years ago
A Cat is on a balcony floor (90cm below the railing), keenly eyeing a butterfly hovering 60 cm above the railing. With what spee
GenaCL600 [577]

We will have the following:

First, the equation to use is the following:

d=v_ot+\frac{1}{2}at^2

Now, we transform the total distance the cat would need to travel:

90\operatorname{cm}+60\operatorname{cm}=150\operatorname{cm}\cdot\frac{1m}{100\operatorname{cm}}=1.5m

So, the cat would need to travel 1.5 meters. ("d" in the equation).

Now, using the speed given we determine the time it would take the cat to traverse the 1.5 meters:

t=\frac{1.5m\cdot1s}{0.45m}\Rightarrow t=\frac{10}{3}\Rightarrow t=3.333\ldots

So, the time it would take the cat to traverse the distance will be approximately 3.33 seconds.

Now, we know that the acceleration will be given by Earth's gravity, so:

1.5m=v_0(\frac{10}{3}s)+\frac{1}{2}(-\frac{9.8m}{s^2})(\frac{10}{3}s)^2\Rightarrow1.5m=v_0(\frac{10}{3}s)+(-\frac{490}{9}m)\Rightarrow\frac{1007}{18}m=v_0(\frac{10}{3}s)\Rightarrow v_0=\frac{1007}{60}\frac{m}{s}\Rightarrow v_0=16.78333\ldots

So, the initial vvelocity the cat must leave the floor in order to arrive at the butterfly with the optimum pouncing speed of 0.45 m/s is approximately 16.78 m/s or exactly 1007/60 m/s.

5 0
2 years ago
When a metal sphere is dropped in to a tall cylinder containing liquid its acceleration is g/2 (gravity over 2). Shaow that : de
Alekssandra [29.7K]

Answer:

Fm is the net force down on the metal in air

Fm / 2 is the net force down on the metal in liquid

Fl is the buoyant force on the metal due to liquid

Fm - Fl = Fm / 2      equating upward and downward forces

Fm / 2 = Fl    

The specific gravity of the metal is twice that of the liquid

Note: F = M g = ρ V g     since ρ = M / V

4 0
2 years ago
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