A local university has a student population that is 55% male. 60% of students are undergraduates. 38% are both male and undergra
1 answer:
The probability that a randomly selected student is female and an undergraduate = 37%
The probability of being female or an undergraduate= 1.05
<h3>The male students</h3>The male population = 55%
Therefore female population would be 1 - 0.55 = 45%
<u>Undergraduates</u> = 60%
The male undergraduate = 38%
Therefore female undergraduates = 60%-38%
= 22%
a. The probability that a randomly selected student is an undergraduate and female
=
= 37%
B. The probability that the student is female or undergraduate
P(A or B)
= Probability of female = 45/100
Probability of undergraduate = 60/100
= 0.45 + 0.60
= 1.05
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