Answer:
A) a = 73.304 rad/s²
B) Δθ = 3665.2 rad
Explanation:
A) From Newton's first equation of motion, we can say that;
a = (ω - ω_o)/t. We are given that the centrifuge spins at a maximum rate of 7000rpm.
Let's convert to rad/s = 7000 × 2π/60 = 733.04 rad/s
Thus change in angular velocity = (ω - ω_o) = 733.04 - 0 = 733.04 rad/s
We are given; t = 10 s
Thus;
a = 733.04/10
a = 73.304 rad/s²
B) From Newton's third equation of motion, we can say that;
ω² = ω_o² + 2aΔθ
Where Δθ is angular displacement
Making Δθ the subject;
Δθ = (ω² - ω_o²)/2a
At this point, ω = 0 rad/s while ω_o = 733.04 rad/s
Thus;
Δθ = (0² - 733.04²)/(2 × 73.304)
Δθ = -537347.6416/146.608
Δθ = - 3665.2 rad
We will take the absolute value.
Thus, Δθ = 3665.2 rad
Asbestos would most likely be found <u>around pipes</u> in a house.
Asbestos is nan organic naturally occurring mineral.
Its composition is similar to thin fibers like crystals of of silicate mineral.
The fibers of Asbestos are so thin and microscopic that they liberate into the atmosphere due to erosion and other processes.
These tiny particles are considered harmful for health as they are carcinogenic in nature and causes mesothelioma.
Its melting point is between 400 to 1,040 °C and is available in blue, green, grey white and yellow color.
If you need to learn more about asbestos click here:
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11. protect the cell and keep its shape.
12. chloroplast
In 1912, Bohr<span> was working for the Nobel laureate J.J. Thompson in England when he was introduced to Ernest Rutherford, whose </span>discovery<span> of the nucleus and development of an atomic model had earned him a Nobel Prize in chemistry in 1908. Under Rutherford's tutelage, </span>Bohr<span> began studying the properties of atoms.
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Answer:
0.05
Explanation:
Divide the mass of the solute by the total volume of the solution. Write out the equation C = m/V, where m is the mass of the solute and V is the total volume of the solution. Plug in the values you found for the mass and volume, and divide them to find the concentration of your solution.
