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3 years ago

12

How much time does it take a person to walk 12 km north at a velocity of 6.5 km/hr

1 answer:

Stella [2.4K]3 years ago

3 0

1.8461 km/hr Well i need more characters so i might as well type a beautiful sentence for you to read and waste your time on.

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You overhear two students discussing the topic of Doppler shift.

9966 [12]

Answer:

agree with student 2, disagree with student 1

Explanation:

If you want to know if the wavelength of light was shifted you have to know the original wavelengths

Since we know the absorption spectrum for elements like hydrogen, we can look for these absorption lines in the star's spectra and figure out what direction these lines are shifted and tell if the star is moving away or towards us

The color of the star refers to the temperature of the star's surface which is not related to the doppler shift of the star

5 0

3 years ago

What do the peaks represent

monitta

An exothermic reaction is a chemical reaction that releases heat. It gives net energy to its surroundings. That is, the energy needed to initiate the reaction is less than the energy released. ... Δ H = (energy used in forming product bonds) − (energy released in breaking reactant bonds)

6 0

4 years ago

Find the west component of 45 m 19º S of W

BaLLatris [955]

Answer:

The west component of the given vector is - 42.548 meters.

Explanation:

We need to translate the sentence into a vectoral expression in rectangular form, which is defined as:

$(x, y) = (r_{x}, r_{y})$

Where:

$r_{x}$ - Horizontal component of vector distance, measured in meters.

$r_{y}$ - Vertical component of vector distance, measured in meters.

Let suppose that east and north have positive signs, then we get the following expression:

$(x, y) = (-45\cdot \cos 19^{\circ}, -45\cdot \sin 19^{\circ})\,[m]$

$(x, y) = (-42.548,-14.651)\,[m]$

The west component corresponds to the first component of the ordered pair. That is to say:

$x = -42.548\,m$

The west component of the given vector is - 42.548 meters.

8 0

4 years ago

The concepts in this problem are similar to those in Multiple-Concept Example 4, except that the force doing the work in this pr

steposvetlana [31]

Answer:

Explanation:

Given that:

distance (z) = 7.86 m

mass of the person = 81.7 kg

Acceleration (a) = 0.729 m/s²

By using Newton's second law along the vertical axis:

$T - mg = ma\\ \\ T = ma + mg \\ \\ T = m(a+g) \\ \\$

T = 81.7 (0.729 +9.8)

T = 860.22 N

The work done now is:

$W_T = T\times z \\ \\$

$W_T = 860.22 \times 7.86$

$\mathbf{W_T =6761.3292\ N}$

5 0

3 years ago

Suppose that two objects attract each other with a gravitational force of 50N. If the mass

jekas [21]

Answer:

F' = 112.5 N

Explanation:

The force of gravitation between two objects is given by Newton's Law of Gravitation as follows:

$F = \frac{Gm_{1}m_{2}}{r^2}\\$ ______________ equation (1)

where,

F = Force = 50 N

G = universal gravitational constant

m₁ = mass of the first object

m₂ = mass of the second object

r = distance between objects

Now, the masses of each object are tripled and the distance between them is doubled:

m₁' = 3m₁

m₂' = 3m₂

r' = 2r

Hence, the new force will be:

$F' = \frac{G(3m_{1})(3m_{2})}{(2r)^2}\\\\F' = \frac{9}{4}\frac{Gm_{1}m_{2}}{r^2}$

using equation (1), we get:

F' = 2.25 F = 2.25(50 N)

<u>F' = 112.5 N</u>

3 0

3 years ago