It’s the skin on the palm of your hand including your fingers. As well as for your toes and soles of your feet.
Answer:
The final speed after the loading is completed is 1.764 m/s
Explanation:
Given;
mass of open train car, m₁ = 2130 kg
initial speed of the car, u₁ = 2.93 m/s
loading rate of gravel = 465 kg/s
time of loading = 3.03 s
mass of the gravel, m₂ = 465 kg/s x 3.03 s = 1408.95 kg
From the principle of conservation of linear momentum
m₁u₁ + m₂u₂ = v(m₁+m₂)
where;
v is the final speed after the loading is completed
2130 x 2.93 + 0 = v (2130 + 1408.95)
6240.9 = v (3538.95)
v = 6240.9/3538.95
v = 1.764 m/s
Therefore, the final speed after the loading is completed is 1.764 m/s
Here is your answer
Velocity of car= 5 m/s
Time= 10 secs
We know that
Displacement = Velocity × time
So,
d= v×t= 5×10 m= 50 m
HOPE IT IS USEFUL
Answer:
K_A = 32.2 10⁶ J
Explanation:
In this exercise we must relate the quantities given to find the kinetic energy
Asteroid A data
m_A = 3.5 m_B
v_A = 2.0 v
they also give the value of the kinetic energy of asteroid A
K_B = 2.3 10⁶ J
the expression for scientific energy is
K = ½ m v²
let's replace
K_A = ½ m_a V_a2
K_A = ½ 3.5 m_B (2.0 v_B)^2
K_A = 3.5 2² (½ m_B v_B²)
K_A = 14 K_B
K_A = 32.2 10⁶ J
