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Molodets [167]
2 years ago
10

Find the momentum of a body of mass 5kg moving with velocity of 4.5m/s​

Physics
1 answer:
Mnenie [13.5K]2 years ago
7 0

Momentum= mass × velocity

momentum= P

P= m×v

P= 5×4.5

P=22.5

I hope this helps.

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3 years ago
A 5 kg object is moving in a straight-line with an initial speed of v m/s. It takes 13 s for the speed of the object to increase
coldgirl [10]

The object's kinetic energy changes according to

d<em>K</em>/d<em>t</em> = 15 J/s

If <em>v</em> is the object's initial speed, then its initial kinetic energy is

<em>K</em> (0) = 1/2 (5 kg) <em>v</em> ²

Use the fundamental theorem of calculus to solve for <em>K</em> as a function of time <em>t</em> :

K(t) = K(0) + \displaystyle\int_0^t \left(15\frac{\rm J}{\rm s}\right)\,\mathrm du = \dfrac12 (5\,\mathrm{kg}) v^2 + \left(15\dfrac{\rm J}{\rm s}\right)t

After <em>t</em> = 13 s, the object's kinetic energy is

<em>K</em> (13 s) = 1/2 (5 kg) (13 m/s)² = 422.5 J

Put this as the left side in the equation above for <em>K(t)</em> and solve for <em>v</em> :

422.5\,\mathrm J = \dfrac12 (5\,\mathrm{kg}) v^2 + \left(15\dfrac{\rm J}{\rm s}\right)(13\,\mathrm s)

==>   <em>v</em> ≈ 9.5 m/s

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2 years ago
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3 years ago
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Although the temperature gradient changes from region to region in the homosphere, there is one gradient that stays the same. it
bezimeni [28]

Answer: the answer is air gradient

Explanation:

3 0
3 years ago
A boy reaches out of a window and tosses a ball straight up with a speed of 10 m/s. The ball is 20 m above the ground as he rele
kirill115 [55]

Explanation:

It is given that,

Speed of the ball, v = 10 m/s

Initial position of ball above ground, h = 20 m

(a) Let H is the maximum height reached by the ball. It can be calculated using the conservation of energy as :

\dfrac{1}{2}mv^2=mgh'            

h'=\dfrac{v^2}{2g}

h'=\dfrac{(10)^2}{2\times 9.8}

h' = 5.1 m

The maximum height above ground,

H = 5.1 + 20

H = 25.1 meters

So, the maximum height reached by the ball is 25.1 meters.

(b) The ball's speed as it passes the window on its way down is same as the initial speed i.e. 10 m/s.

Hence, this is the required solution.                              

6 0
3 years ago
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