In the above givem figures all the angles can be found by complementary pair of angles.
What do you mean by complementary pair of angles?
- There are basically two types of pair of angles i.e. Supplementary & Complementary.
- <em>Supplementary means that sum of two angles is 180°. It is also known as linear pair of angles. It is always formed on straight line.</em>
- <em>Complementary</em><em> </em><em>pair</em><em> </em><em>of</em><em> </em><em>angle</em><em> </em><em>is</em><em> </em><em>that</em><em> </em><em>when</em><em> </em><em>sum</em><em> </em><em>of</em><em> </em><em>both</em><em> </em><em>angles</em><em> </em><em>is</em><em> </em><em>90</em><em>°</em><em>.</em><em> </em><em>It</em><em> </em><em>is</em><em> </em><em>formed</em><em> </em><em>when</em><em> </em><em>a</em><em> </em><em>right</em><em> </em><em>angle</em><em> </em><em>is</em><em> </em><em>bisected</em><em>.</em>
<h3>
<em>F</em><em>u</em><em>n</em><em> </em><em>Fact</em><em>:</em><em> </em><em>All</em><em> </em><em>angles</em><em> </em><em>of</em><em> </em><em>a</em><em> </em><em>square</em><em> </em><em>and</em><em> </em><em>rectangle</em><em> </em><em>are</em><em> </em><em>of</em><em> </em><em>90</em><em>°</em><em>.</em></h3>
<h2>
#a</h2>
<u> ∠A+45°=90°</u>
<u> ∠A+45°=90° ∠A=90°-45°</u>
<u> ∠A+45°=90° ∠A=90°-45° ∠A=45°</u>
Hence, ∠A is 45°
<h2>
#b</h2>
<u> ∠</u><u>B</u><u>+</u><u>65</u><u>°</u><u>=</u><u>90</u><u>°</u>
<u> ∠</u><u>B</u><u>=</u><u>90</u><u>°</u><u>-65</u><u>°</u>
<u> ∠</u><u>B</u><u>=</u><u>25</u><u>°</u>
Hence, ∠B is 25°
<h2>
#c</h2>
<u> ∠</u><u>C</u><u>+</u><u>52</u><u>°</u><u>=</u><u>90</u><u>°</u>
<u> ∠</u><u>C</u><u>=</u><u>90</u><u>°</u><u>-52</u><u>°</u>
<u> ∠</u><u>C</u><u>=</u><u>38</u><u>°</u>
Hence, ∠C is 38°
<h2>
#d</h2>
<u> ∠</u><u>D</u><u>+</u><u>40</u><u>°</u><u>+</u><u>34</u><u>°</u><u>=</u><u>90</u><u>°</u>
<u> ∠</u><u>D</u><u>+</u><u>74</u><u>°</u><u>=</u><u>90</u><u>°</u>
<u> ∠</u><u>D</u><u>=</u><u>90</u><u>°</u><u>-</u><u>7</u><u>4</u><u>°</u>
<u> ∠</u><u>D</u><u>=</u><u>16</u><u>°</u>
Hence, ∠D is 16°
Answer:
a) Lateral area of the solid = 2011.43 
b) Surface area of the solid = 2544 
Step-by-step explanation:
a) Lateral area of the figure = 2
rh
where; r is the radius of the cylinder, and h is its height.
Lateral area of the figure = 2 x
x 10 x 32
= 2011.43 
b) The surface area = 2
r(r + h) - 2(
x b x h)
= 2
r(r + h) - (b x h)
The height of the isosceles triangle can be determined by applying the Pythagoras theorem to have,
=
+ 
100 = 36 + 
= 100 - 36
= 64
h = 
= 8
h = 8 cm
The surface area of the solid = 2 x
x 10 (10 + 32) - 12 x 8
= 2640 - 96
= 2544
The surface area of the solid is 2544
.
From x + 3y = -5, y = -x/3 - 5, so the slope of the line is -1/3. The slope of the new line is also -1/3, so y = -x/3 + B. Pugging in x = 2 and y = -7, we get -7 = -2/3 + B, so B = -19/3.
Then the line is y = -x/3 - 19/3. Then 3y = -x - 19, so 3y + x = -19. We want the right-hand side to be 3, so we mutiply both sides by -3/19: -9/19*y - 3/19*x = 3. Therefore, A + B = -9/19 - 3/19 = -12/19.
I believe that the answer to this is b
Y=-6(x+1)^2-7
This Is The Correct Answer :), Hope This Helps!