Ask question

Ask question

All categories

3 years ago

11

There are 3 boys to every 5 girls in mrs. kennedy's class. if there are 40 students in the class, how many of those students are

girls?

1 answer:

Gala2k [10]3 years ago

4 0

Ratio of girls to boys = 5/3

Number of girls in 40 students would be 3/5 * 40 = 24

You might be interested in

HELP WITH THIS QUESTION, ASAP!!

alukav5142 [94]

The answer to that question is b

6 0

3 years ago

An appliance repairman charges $35

Schach [20]

Answer:

3 hours.

Step-by-step explanation:

I'm assuming that you are asking how many hours the repairman worked in this problem. To find the solution, use the equation $125=35+ 30x.

3 0

3 years ago

Which will have a higher effective interest rate - a payday loan for $1500 that

Andrew [12]

Answer:

B. A payday loan for $1500 that is due in 10 days with a fee of $90, since it has the shorter period

8 0

2 years ago

(Math never got easier!) No seriously help:)

Diano4ka-milaya [45]

Answer:

Step-by-step explanation:

cosФ=0 then the angle=π/2=90 degrees

sinФ==1 sin 90=1

12) the original price of the console that Amanda bought :

240+(240*50%)=360 dollars

the price before the tariffs:

360-(360*50^)=180 dollars

8 0

3 years ago

One side of a triangle is increasing at a rate of 9 cm/s and a second side is decreasing at a rate of 2 cm/s. if the area of the

LenKa [72]

Use the attached figure to guide yourself through the explanation. In the figure:
$a=21cm, b=36cm, \widehat{C}=\frac{\pi}{6}$ .
We know that:
$\frac{da}{dt}=9,\frac{db}{dt}=-2$
Also remmeber that the area of a triangle is:
$A=\frac{Base\times Height}{2}$
The hegiht is shown in the figure in red, the base is just the b side.
Using the angle C the area of the triangle is:
$A=\frac{1}{2}ab\cos(\widehat{C})\implies2A=ab\cos(\widehat{C})$
Now taking the derivative of the area 2A with respect to t we have:
$2\frac{dA}{dt}=b\cos(\widehat{C})\frac{da}{dt}+a\cos(\widehat{C})\frac{db}{dt}-ab\sin(\widehat{C})\frac{d\widehat{C}}{dt}$

Replacing with the right values:
$\frac{dA}{dt}=0\\
\\
\cos({\widehat{C}})=\frac{\sqrt{3}}{2}\\ \\
\sin({\widehat{C}})=\frac{1}{2}\\ \\

$
yields:
$0=36\frac{\sqrt{3}}{2}.9-21\frac{\sqrt{3}}{2}.2-\frac{1}{2}.21.36.\frac{d\widehat{C}}{dt}\implies \frac{d\widehat{C}}{dt}=\frac{141}{378}\sqrt{3}$

5 0

3 years ago