A rod of length 35.50 cm has linear density (mass per length) given by λ = 50.0 + 23.0x where x is the distance from one end, an
1 answer:
Answer:
(a)20.65g
(b)0.19m
Explanation:
(a) The total mass would be it's mass per length multiplied by the total lenght
0.355(50 + 23*0.355) = 20.65 g
(b) The center of mass would be at point c where the mass on the left and on the right of c is the same
Hence the mass on the left side would be half of its total mass which is 20.65/2 = 10.32 g
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Answer:
217.43298 m/s
Explanation:
= Mass of bullet = 19 g
= Mass of bob = 1.3 kg
L = Length of pendulum = 2.3 m
= Angle of deflection = 60°
u = Velocity of bullet
Combined velocity of bullet and bob is given by
As the momentum is conserved
The speed of the bullet is 217.43298 m/s
Answer:
The work done by the hoop is equal to 5.529 Joules.
Explanation:
Given that,
Mass of the hoop, m = 96 kg
The speed of the center of mass, v = 0.24 m/s
To find,
The work done by the hoop.
Solution,
The initial energy of the hoop is given by the sum of linear kinetic energy and the rotational kinetic energy. So,
I is the moment of inertia,
Since,
Finally it stops, so the final energy of the hoop will be,
The work done by the hoop is equal to the change in kinetic energy as :
W = -5.529 Joules
So, the work done by the hoop is equal to 5.529 Joules. Therefore, this is the required solution.