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Olin [163]
3 years ago
9

A spherical, conducting shell of inner radius r1= 10 cm and outer radius r2 = 15 cm carries a total charge Q = 15 μC . What is t

he magnitude of the electric field at a distance (a) r = 12 cm, and (b) r = 20 cm from the center of the shell? (k = 1/4πε0 = 8.99 × 109 N ∙ m2/C2)
Physics
1 answer:
lutik1710 [3]3 years ago
4 0

a) E = 0

b) 3.38\cdot 10^6 N/C

Explanation:

a)

We can solve this problem using Gauss theorem: the electric flux through a Gaussian surface of radius r must be equal to the charge contained by the sphere divided by the vacuum permittivity:

\int EdS=\frac{q}{\epsilon_0}

where

E is the electric field

q is the charge contained by the Gaussian surface

\epsilon_0 is the vacuum permittivity

Here we want to find the electric field at a distance of

r = 12 cm = 0.12 m

Here we are between the inner radius and the outer radius of the shell:

r_1 = 10 cm\\r_2 = 15 cm

However, we notice that the shell is conducting: this means that the charge inside the conductor will distribute over its outer surface.

This means that a Gaussian surface of radius r = 12 cm, which is smaller than the outer radius of the shell, will contain zero net charge:

q = 0

Therefore, the magnitude of the electric field is also zero:

E = 0

b)

Here we want to find the magnitude of the electric field at a distance of

r = 20 cm = 0.20 m

from the centre of the shell.

Outside the outer surface of the shell, the electric field is equivalent to that produced by a single-point charge of same magnitude Q concentrated at the centre of the shell.

Therefore, it is given by:

E=\frac{Q}{4\pi \epsilon_0 r^2}

where in this problem:

Q=15 \mu C = 15\cdot 10^{-6} C is the charge on the shell

r=20 cm = 0.20 m is the distance from the centre of the shell

Substituting, we find:

E=\frac{15\cdot 10^{-6}}{4\pi (8.85\cdot 10^{-12})(0.20)^2}=3.38\cdot 10^6 N/C

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miss Akunina [59]

Answer:

1) the unit of power is A.Watt

2)100J=50W

100=50s

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10. Heat is the transfer of thermal energy from one object to another because of a difference in
stiv31 [10]

Answer:

Temperature

Explanation:

Heat only flows from one point to the other due to the difference in temperature.

7 0
3 years ago
A man at point A directs his rowboat due north toward point B, straight across a river of width 100 m. The river current is due
prohojiy [21]

Answer:

1.35208 m/s

Explanation:

Speed of the boat = 0.75 m/s

Distance between the shores = 100 m

Time = Distance / Speed

Time=\frac{100}{0.75}=133.33\ s

Time taken by the boat to get across is 133.33 seconds

Point C is 150 m from B

Speed = Distance / Time

Speed=\frac{150}{\frac{100}{0.75}}=1.125\ m/s

Velocity of the water is 1.125 m/s

From Pythagoras theorem

c=\sqrt{0.75^2+1.125^2}\\\Rightarrow c=1.35208\ m/s

So, the man's velocity relative to the shore is 1.35208 m/s

3 0
3 years ago
A proton and an electron are fixed in space with a separation of 859 nm. Calculate the electric potential at the midpoint betwee
makkiz [27]

Answer:

The electric potential at the midpoint between the two particles is 3.349 X 10⁻³ Volts

Explanation:

Electric potential is given as;

V = E*r

where;

E is the electric field strength, = kq/r²

V = ( kq/r²)*r

V = kq/r

k is coulomb's constant = 8.99 X 10⁹ Nm²/C²

q is the charge of the particles = 1.6 X 10⁻¹⁹ C

r is the distance between the particles = 859 nm

At midpoint, the distance = r/2 = 859nm/2 = 429.5 nm

V = (8.99 X 10⁹  * 1.6 X 10⁻¹⁹)/ (429.5 X 10⁻⁹)

V = 3.349 X 10⁻³ Volts

Therefore, the electric potential at the midpoint between the two particles is 3.349 X 10⁻³ Volts

3 0
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